When constructing perpendicular lines with a compass and straightedge, how should you start the construction?

1 answer:

6 0

1.) Draw a line segment somewhere on the paper and label it line m.
2.) Mark a point somewhere on the paper but not on the line, label this point r.
3.) Fold the paper on point r. Make sure the line is folded in top of itself
4.)Trace the fold with your pencil/pen
5.) label the intersection point P

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What is the equation of the line that passes through (-3, -1) and has a slope of 2/5? Put your answer in slope-intercept form.

Zanzabum

Hi there!

The general formula of A line in slope-intercept form is the following:
$y = mx + n$

In this formula m represents the slope of the line. Therefore, we can conclude that m = 2/5.
$y = \frac{2}{5} x + n$

We also know that the line passes through the point (-3, -1) and we can therefore substitute this coordinate into the formula of the line.
x = -3 and y = -1

$- 1 = \frac{2}{5} \times - 3 + n$

Multiply first.
$- 1 = - 1\frac{1}{5} + n$

And finally add 1 1/5 to both sides of the equation.
$\frac{1}{5} = n$

We can now switch sides.
$n = \frac{1}{5}$

Now we've found our value of n, which we can substitute into the formula of our line. Hence, in slope-intercept form, we find the following:
$y = \frac{2}{5} x + \frac{1}{5}$

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