Given that quadrilateral QRST is a square.
Each angle of a square is of 90 degrees.
Angle <RQT is also an angle of 90 degrees.
We also given angle RQT = 3x - 6.
So, we can setup an equation as 3x-6 =90.
Now, we need to solve the equation for x.
6 is being subtracted from left side.
We always apply reverse operation. Reverse operation of subtraction is addition.
So, adding 6 on both sides of the equation, we get
3x-6+6 =90+6.
3x = 96.
3 is being multipied with x, in order to remove that 3, we need to apply reverse operation of multiplication.
So, dividing both sides by 3.
x=32 (final answer).
Answer: the third angle is 106 degrees.
The base angles are 37 degrees each.
Step-by-step explanation:
In an isosceles triangle, the base angles are equal.
Let x represent the measure of each of the base angles.
The third angle in an isosceles triangle is 32 more than 2 times as large as each of the two base angles. It means that the measure of the third angle would be
(2x + 32) degrees
The sum of the angles inna triangle is 180 degrees. It means that
x + x + 2x + 32 = 180
4x = 180 - 32
4x = 148
x = 37
The third angle is
2x = 32 = (2 × 37) + 32
= 74 + 32 = 106
pato apni sa pato bata is sa dak na sa kuch bi nahi mila ga
Answer x=-2,-6
The roots (zeros) are the
x
x
values where the graph intersects the x-axis. To find the roots (zeros), replace
y
y
with
0
0
and solve for
x
x
.
Answer:
Banana = 6, the rest is in the picture
Step-by-step explanation:
