Pretty sure you already had something posted about this... in case you've lost it, or have questions:
#25 is fairly simple. Plug in -4 and 3 into the equation, and the extraneous root will be the one that does not work.
Extraneous root in this case is positive four since +4≠-4
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</span>In this case it's negative 3, since -3≠3
#29 can be turned into a quadratic equation.
Square both sides to get
Then bring the 2x+3 to the other side, setting the quadratic equal to zero.
Factor to find that it's equivalent to
(x-3)(x+1)=0
Therefore x is equal to positive 3 and negative 1. Plug both back into the original equation. Whichever does not work is the extraneous root, and the answer is the one that does.
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</span>Extraneous root would be negative 3.
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</span>Extraneous root would be positive 1.
Your answers are positive 3 and negative 1.
<span>Extraneous roots are negative 3 and positive 1.</span>
Step-by-step explanation:
The first one has x going up by 2's and y going up by 1's. The second has x going up by 1's and y going up by 2's.
Answer:
Expression
Step-by-step explanation:
Answer:
True
Step-by-step explanation:
Given data
Diameter =6 yards
Radius R= Diameter/2= 6/2 = 3 yards
R²=3*3=9square yards
Hence R^2 = 9square yards= True
Answer:
x=7
Step-by-step explanation:
5-(-7) = 5+ x
Distribute the negative 1
5 + -1*-7=5+x
5+7=5+x
Combine like terms (add 5 and 7)
12=5+x
Subtract 5 from both sides
7=x