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mamaluj [8]
3 years ago
13

There are two types of boxes containing mangoes. Each box of the larger type contains four more mangoes than the number of mango

es contains in 8 boxes of the smaller type. Each larger box contains 100 mangoes. Find the no of mangoes contain in the smaller box.
Mathematics
1 answer:
Ket [755]3 years ago
6 0

Answer:

12

Step-by-step explanation:

(100-4)/8

12

that the answer

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Hi can you help me Find h?<br> Find h
AlekseyPX

Answer:

6

Step-by-step explanation:

3 0
2 years ago
Huda purchased 200 beads for AED 48 to make necklace. if she needs to buy 25 more beads, how much will she pay if she is charged
Natasha_Volkova [10]
She would need to spend 6 more. To find this answer, you divide 48 by 200 to see how much each bead costs, and then you multiply that amount by 25.
3 0
3 years ago
10 ÷ (20 ÷ 2² × 5 ÷ 5) × 8 - 2
dangina [55]
Use PEMDAS:

P arenthesis
E xponents
M ultiplication
D ivision
A dd
S ubstract

Paranthesis and Exponents
(20 / 2^2 * 5 / 5) = 5

Multiplication
5*8= 40

Division
10 / 40 = 0.25

Subtraction
0.25 - 2 = −1.75

Therefore,
The answer is -1.75


5 0
3 years ago
The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15%
vagabundo [1.1K]

Answer:

1) \chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313

2) p_v =P(\chi^2_{3}>16.313)=0.000978

And we got the same decision reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts

The Chi-Square test of independence is used "to determine if there is a significant relationship between two nominal (categorical) variables". And is defined with the following statistic:

\chi^2 =\sum_{i=1}^n \frac{(O-E)^2}{E}

Where O rpresent the observed values and E the expected values.  

State the null and alternative hypothesis

Null hypothesis: The distribution  is 30% catfish, 15% bass, 40% bluegill, and 15% pike

Alternative hypothesis: The distribution  is NOT 30% catfish, 15% bass, 40% bluegill, and 15% pike

The observed values are given by the table given:

Catfish =112, BAss = 95, Bluegill=210, Pike=83

Calculate the expected values

In order to calculate the expected values we can use the following formula for each cell of the table

E = \% Grand total

E_{Catfish}=500*0.3=150

E_{Bass}=500*0.15=75

E_{Bluegill}=500*0.4=200

E_{Pike}=500*0.15=75

Part 1: Calculate the statistic

\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313

\chi^2 =16.313

Calculate the critical value

First we need to calculate the degrees of freedom given by:

df= (categories-1)=(4-1)= 3

Since the confidence provided is 95% the significance would be \alpha=1-0.95=0.05 and we can find the critical value with the following excel code: "=CHISQ.INV(0.95,3)", and our critical value would be \chi^2_{crit}=7.815

We can calculate also the p value:

p_v =P(\chi^2_{3}>16.313)=0.000978

And we got the same decision reject the null hypothesis at 5% of significance.

5 0
3 years ago
Barry is selling magazine subscriptions for a school fundraiser. He has already sold 15 subscriptions. He plans to sell 3 subscr
olya-2409 [2.1K]

Answer:

5 more weeks

Step-by-step explanation:

5 more weeks if he already sold 15. 10 more weeks if you exclude the 15 he already sold.

3 0
3 years ago
Read 2 more answers
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