Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Answer:
A. LCM=72 B. GCF=7 C. 7(5+9)
Step-by-step explanation:
A. 8/2=4/2=2 9/3=3 Use the denominators to find the LCM. In this case, the LCM is 72.
B. 35/5=7 63/3=21/3=7 The GCF for these numbers is 7 because it is the only factor that they have in common.
C. 7 x 14=88 Since 5 and 9 don't have common factors, they work perfectly for this problem.
Simple...
you have: 8x-6y=1
You're trying to find m-->>using y=mx+b to re-write the line....
8x-6y=1
8x-6y=1
-8x -8x
-6y=-8x+1

y=
Your slope m=
Thus, your answer.
Answer:
4
Step-by-step explanation:
because The square root of 16 is 4, which is a rational number.