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4 years ago

Will reward brainliest. Geometry

Mathematics

1 answer:

bixtya [17]4 years ago

7 0

Answer:

D. 150

Step-by-step explanation:

Arc AB is formed by the central angle with measure 150°.

So, the arc has the same measure.

AB = 150

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Function P is defined as P (x) = x ^2 . Explain why P (2) + P (3) isn't equal to P (5) .

diamong [38]

Answer:

P(x) = x + 2

Piden: A = P(P(P(P(3))))

P(3); x = 3

P(3) = 3 + 2 = 5

A = P(P(P(P(3))))

A = P(P(P(5)))

P(5); x = 5

P(5) = 5 + 2 = 7

A = P(P(P(5)))

A = P(P(7))

P(7); x = 7

P(7) = 7 + 2 = 9

A = P(P(7))

A = P(9)

P(9); x = 9

P(9) = 9 + 2 = 11

→ A = P(P(P(P(3)))) = 11

Step-by-step explanation:

listo e

4 0

4 years ago

Do these equations have infinite solutions 2x + 5y= 31 and 6x -y = 13

katovenus [111]

$2x = 31 - 5y \\ x = \frac{31}{2} - \frac{5}{2}y$

$6x = 13 + y \\ x = \frac{13}{6} + \frac{1}{6} y$

8 0

4 years ago

What is 2x x54 <br> people with the best answer get a friend reqised

sergejj [24]

2x X 54 is going to be 108x

since both are positive you will get a positive #
54 X 2 is 108

6 0

3 years ago

A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 5 large boxes and 2 small boxes has a t

nikdorinn [45]

Each large box weighs 15 kilograms and each small box weighs 13.5 kilograms.

Step-by-step explanation:

Let,

Weight of large box = x

Weight of small box = y

According to given statement;

5x+2y=102 Eqn 1

3x+8y=153 Eqn 2

Multiyplying Eqn 1 by 4

$4(5x+2y=102)\\20x+8y=408\ \ \ Eqn\ 3$

Subtracting Eqn 2 from Eqn 3

$(20x+8y)-(3x+8y)=408-153\\20x+8y-3x-8y=255\\17x=255$

Dividing both sides by 17

$\frac{17x}{17}=\frac{255}{17}\\x=15$

Putting x=15 in Eqn 2

$15(3)+8y=153\\45+8y=153\\8y=153-45\\8y=108$

Dividing both sides by 8

$\frac{8y}{8}=\frac{108}{8}\\y=13.5$

Each large box weighs 15 kilograms and each small box weighs 13.5 kilograms.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

4 0

4 years ago

A basketball player stands near the middle of the court and throws the ball toward the basket.

kompoz [17]

Answer:

A function to represent the height of the ball in terms of its distance from the player's hands is $y=\frac{-1}{54}(x-18)^2+12$

Step-by-step explanation:

General equation of parabola in vertex form $y= a(x-h)^2+k$

y represents the height

x represents horizontal distance

(h,k) is the coordinates of vertex of parabola

We are given that The ball travels to a maximum height of 12 feet when it is a horizontal distance of 18 feet from the player's hands.

So,(h,k)=(18,12)

Substitute the value in equation

$y=a(x-18)^2+12$ ---1

The ball leaves the player's hands at a height of 6 feet above the ground and the distance at this time is 0

So, y = 6

So, $6=a(0-18)^2+12$

6=324a+12

-6=324a

$\frac{-6}{324}=a$

$\frac{-1}{54}=a$

Substitute the value in 1

So, $y=\frac{-1}{54}(x-18)^2+12$

Hence a function to represent the height of the ball in terms of its distance from the player's hands is $y=\frac{-1}{54}(x-18)^2+12$

8 0

4 years ago