PLEASE HELP WILL GIVE BRAINLIST.<br> What is the slope of the line in the graph?

Of 580580 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compa

Lubov Fominskaja [6]

Answer:

a) The 99% confidence interval would be given (0.204;0.296).

b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation

n=580 represent the random sample taken

X represent the seafood sold in the country that is mislabeled or misidentified by the people

$\hat p=0.25$ estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

$\alpha=0.01$ represent the significance level (no given, but is assumed)

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.25 - 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.204$

$0.25 + 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.296$

And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).

Part c

A government spokesperson claimed that the sample size was too small, relative to the billions of pieces of seafood sold each year, to generalize. Is this criticism valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

4 0

3 years ago

12. If 5t + 2 = 6, then t =

tankabanditka [31]

It would be t=0.8, mainly bc you subtract two from six , that reduces it to four
then you divide four by five and it should give you your answer
and to chack your work put .8 where t was and solve

6 0

3 years ago

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Gina bought 2.3 pounds of red apples and 2.42 pounds of green apples. They were on sale for $0.75 a pound. How much did the appl

vampirchik [111]

4. 72•0.75= $3.54 is the correct answer

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3 years ago

Which equation represents a population of 320 animals that decreases at an annual rate of 19%

kotegsom [21]

320 times .19t
t being the number of years

6 0

3 years ago

The Rodriguez family and the Hill family each used their sprinklers last summer. The water output rate for the Rodriguez family'

brilliants [131]

Answer:

x = 23.33 hr Rodriguez sprinkler

y = 26.66 hr Hill sprinkler

Step-by-step explanation: INCOMPLETE QUESTION

Requiered information:

the water output rate for both sprinkler families

We assume : Rodriguez family 40 lts/hr

Hill family 35 lts/ hr

Total water output 1900 lts

and total combined hours working is 50 hr

Let call "x" time in hours sprinkler of Rodriguez family worked

and "y" time in hours sprinkler of Hill family worked

Then if total output was 1900 lts

40*x + 35*y = 1900 and x + y = 50

We have a two equation system, solving

y = 50 - x ⇒ 40*x + 35 * ( 50 - x )

40x = 1750 - 35x

75 x = 1750 ⇒ x = 1750/75 ⇒ x = 23.33 hr

and y = 50 - 23.33 ⇒ y = 26.66 hr

6 0

3 years ago

PLEASE HELP WILL GIVE BRAINLIST. What is the slope of the line in the graph?