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NISA [10]
3 years ago
8

Compute (2i-6)(5+1) where i=√1

Mathematics
2 answers:
jenyasd209 [6]3 years ago
8 0

Answer:

Step-by-step explanation:

hello :

(2i-6)(5+i)=10i+2i²-30-6i    ... i² = -1

(2i-6)(5+i)=10i-2-30-6i = -32+4i

Svetach [21]3 years ago
6 0

Answer:

4i - 32

Step-by-step explanation:

(2i-6)(5+i)

10i - 30 + 2i² - 6i

i=√-1

i² = -1

10i - 30 + 2(-1) - 6i

-30 - 2 + 10i - 6i

-32 + 4i

4i - 32

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