in this problem what you are really looking for is which of these sets is a pathagorean triple. That means it will solve the pathagorean theorem. (a sqaured + b squared = c squared) c is always going to be the largest number or the hypotenuse. if you plug all the number sets into the theorem, only one works and that is 7, 24, 25 which is your answer.
Answer:
x = 24.
r
0.
Step-by-step explanation:
2. The given equation is:

a) To eliminate the fractions multiply the equation throughout by the LCM of the denominators of the fraction. In this case, the LCM of (2, 3). The LCM is 6. So, multiply the entire equation by 6.
b) Half of the difference between an integer and 4 equals the sum of one - third of the integer and 2. Find the integer.
c) We have the equation:

Multiplying throughout by 6, we get:




Therefore, the solution of the equation is 24.
3. The given equation is: 
To solve for y:
We can rearrange the equation as:


or,
Note that we have to impose a condition on variable
. It would be that
can never be zero. i.e.,
. Otherwise, the value of
would be undefined.
The answer is 5/12 because 1/6 converts to 2/6 and 7/12-2/6 is equal to 5/12
[|] Answer [|]
<u><em>6, 5, 4</em></u>
<u><em></em></u>
[|] Explanation [|]
<em>Exterior Angles:</em>
<u><em>Angles facing outward on a triangle</em></u>
Angles 6, 5 and
4 are not inside the main triangle. They are wide open. <u><em>Exterior simply means the outside of something.</em></u> Angles 6, 5 and 4 are the outside angles to the main triangle.
<u><em>_[|] Eclipsed [|] _</em></u>
From the information given,
x represents number of small boxes while y represents number of large boxes.
If each small box can hold 6 books and each large box can hold 10 books, it means that the expression for the number of books that x small boxes and y large boxes can hold is
6x + 10y
If James can pack up to 110 books, it means that the number of books that he can pack is less than or equal to 110. The inequality representing this scenario is
6x + 10y ≤ 110
10y ≤ - 6x + 110
Dividing both sides of the equation by 10, we have
y ≤ - 6x/10 + 110/10
y ≤ - 3x/5 + 11
The graph is shown below
The inequality that represents this sitaution is 6x + 10y ≤ 110
The graph of the inequality wil have solid boundary at y = - 3x/5 + 11
and will be shaded below the line.