How do I do these 2 questions

Mathematics

1 answer:

olga nikolaevna [1]2 years ago

3 0

Q10/

6 m/s = 21.6 km/h

6m/s =3.6 × 6 = 21.6 km/h

** 1m/s = 3.6 km /h

$1 \frac{m}{s} = \frac{1}{1000} km \times \frac{60s}{1 \: min} \times \frac{60 \: min}{ 1\: h} \\ \\ = \frac{1}{1000} \times \frac{3600}{1} \\ \\ = \frac{3600}{1000} = 3. 6\: km/h$

Q14/

7x -1 =3x+7

7x - 3x = 7 +1

4x =8

x = 8/4

x =2

I hope I helped you^_^

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Construct the sampling distribution of the sample means.?

Neko [114]

Answer:

The Sampling Distribution of the Sample Mean. If repeated random samples of a given size n are taken from a population of values for a quantitative variable, where the population mean is μ (mu) and the population standard deviation is σ (sigma) then the mean of all sample means (x-bars) is population mean μ (mu).

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2 years ago

I NEED HELP PLEASE, THANKS! :)

Maksim231197 [3]

Answer:

Option B

Step-by-step explanation:

First identify which options are a match for the hyperbola with a foci of (- 12, 6) and ( 6, 6 ). If there is only one, we can claim that that is the solution. Otherwise we would have to take the vertices into account,

The first option can be eliminated as it is present with a decimal in the denominator, indicating that the foci should also be a decimal. However, the foci of this option should be valuable to us -

$\left(h+c,\:k\right),\:\left(h-c,\:k\right),\\\left(-3+c,\:6\right),\:\left(-3-c,\:6\right),\\c = ( About ) 3.6,\\\\Foci = \left(0.55808 ,\:6\right),\:\left(-6.55808,\:6\right)$