Question

Expand

Answer 1

Answer:

1) $3(x+4)=3x+12$

2) $4(x+5)-2(x-3)=2x+26$

3) $(x+2)(x+7)=x^2+9x+14$

4) $12x-18=6(2x-3)$

Step-by-step explanation:

1) Expression : $3(x+4)$

To find : Expand the expression ?

Solution :

$3(x+4)$

Applying distributive property, $a(b+c)=ab+ac$

$3(x+4)=3x+12$

2) Expression : $4(x+5)-2(x-3)$

To find : Expand and simplify the expression ?

Solution :

$4(x+5)-2(x-3)$

Applying distributive property, $a(b+c)=ab+ac$

$4(x+5)-2(x-3)=4x+20-2x+6$

$4(x+5)-2(x-3)=2x+26$

3) Expression : $(x+2)(x+7)$

To find : Expand the expression ?

Solution :

$(x+2)(x+7)$

Applying distributive property, $a(b+c)=ab+ac$

$(x+2)(x+7)=x(x+7)+2(x+7)$

$(x+2)(x+7)=x^2+7x+2x+14$

$(x+2)(x+7)=x^2+9x+14$

4) Expression : $12x-18$

To find : Factorize the expression ?

Solution :

$12x-18$

Taking the common term,

$12x-18=6(2x-3)$

Answer 2

Answer:

The working of expressions is shown below.

Step-by-step explanation:

We are given the following information:

a) Expand

$3(x+4)\\3\times x + 3\times 4\\3x + 12$

b) Expand and simplify

$4(x+5)-2(x-3)\\=(4x + 20) -(2x-6)\\=( 4x-2x) + (20 + 6)\\= 2x + 26\\=2(x +13)$

c) Expand

$(x+2)(x+7)\\=x\times x + x\times 7 + 2\times x + 2\times 7\\= x^2 + 7x + 2x + 14\\=x^2 + 9x +14$

d) Factorize fully

$12x-18\\=6(2x-3)$