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3 years ago

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Mathematics

1 answer:

Dahasolnce [82]3 years ago

4 0

Exact form : 45/4
Decimal form : 11.25
mixed number form : 11 1/4

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Write the equation of a circle with center (4, -5) and radius = square root of 13

Anon25 [30]

<h2>Hello!</h2>

The answer is:

The equation of the given circle is:

$(x-4)^{2}+(y+5)^{2}=13$

The equation of a circle is given by the following equation:

$(x-h)^{2} +(y-k)^{2}=r^{2}$

We are given the center point (4,-5) and the radius.

So,

Where:

$h=x=4\\k=y=-5\\r=\sqrt{13}$

Then, substituting into the circle equation, we have:

$(x-4)^{2} +(y-(-5))^{2}=(\sqrt{13})^{2}$

Hence, the simplified equation of the circle is:

$(x-4)^{2}+(y+5)^{2}=13$

Have a nice day!

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3 years ago

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Otrada [13]

Answer:

Step-by-step explanation:

The applicable rules of exponents are ...

$(a^b)^c=a^{bc}\\\\\sqrt[n]{a}=a^{1 \! /n}$

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Evaluate -3(6) please help me with this question

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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4 years ago

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