What is a Software that interprets commands drom the keyboard and mouse

Which of the following is an example of a syntax error?

Yuri [45]

Answer:

misspelling a programming language word

Explanation:

Syntax error is the type of error in programming, when the programmer insert some symbol that is not present in directories or libraries, the programmer not followed the rules of that particular programming language that is understandable to compiler.

For example in C++, it is necessary to insert the semicolon (;) after each statement. If the programmer not insert the semicolon after each statement, the program will show the syntax error.

If the programmer use integer instead of int to assign datatype to the variable in C++, it will also leads to the syntax error. Because in C++ library, Integer is defined with the help of "int".

4 0

2 years ago

g Create a program that reads a list of states from an input file, puts them in order, and displays the sorted list to the user.

mixas84 [53]

Answer:

Check the explanation

Explanation:

# Step 1

the first thing to execute will be......

f = open("states.txt")

# Step 2

the second step is......

states = []

for line in f:

states.append(line.strip())

# Step 3:

the third step is to......

for state in sorted(states):

print(state)

f.close()

3 0

2 years ago

Use semaphore(s) to solve the following problem. There are three processes: P1, P2, and P3. Each process Pi has a segment of cod

Lisa [10]

Answer:

See explaination

Explanation:

Here we will use two semaphore variables to satisfy our goal

We will initialize s1=1 and s2=1 globally and they are accessed by all 3 processes and use up and down operations in following way

Code:-

s1,s2=1

P1 P2 P3

P(s1)

P(s2)

C1

V(s2) .

P(s2). .

. C2

V(s1) .

P(s1)

. . C3

V(s2)

Explanation:-

The P(s1) stands for down operation for semaphore s1 and V(s1) stands for Up operation for semaphore s1.

The Down operation on s1=1 will make it s1=0 and our process will execute ,and down on s1=0 will block the process

The Up operation on s1=0 will unblock the process and on s1=1 will be normal execution of process

Now in the above code:

1)If C1 is executed first then it means down on s1,s2 will make it zero and up on s2 will make it 1, so in that case C3 cannot execute because P3 has down operation on s1 before C3 ,so C2 will execute by performing down on s2 and after that Up on s1 will be done by P2 and then C3 can execute

So our first condition gets satisfied

2)If C1 is not executed earlier means:-

a)If C2 is executed by performing down on S2 then s2=0,so definitely C3 will be executed because down(s2) in case of C1 will block the process P1 and after C3 execute Up operation on s2 ,C1 can execute because P1 gets unblocked .

b)If C3 is executed by performing down on s1 then s1=0 ,so definitely C2 will be executed now ,because down on s1 will block the process P1 and after that P2 will perform up on s1 ,so P1 gets unblocked

So C1 will be executed after C2 and C3 ,hence our 2nd condition satisfied.

4 0

3 years ago

Project 1-1: Set Up a Small Network

Wewaii [24]

Answer:

a. peer-to-peer

b star topology

Explanation:

3 0

3 years ago

Design a 128KB direct-mapped data cache that uses a 32-bit address and 16 bytes per block. The design consists of two components

Kitty [74]

Answer:

See the attached pictures for detailed answer.

Explanation:

The cache contain 8K number of blocks.each block has 16 Byte worth of data. Each of these bytes are addressable by block offset. Now, each of these blocks are addressable and their address is provided by line offset or set offset. If block number is given in Decimal format then the block to which that block will be mapped is given by expression

mappedToBlock = (bNumber)mod213

TAG and valid but consititues something called cache controller. TAG holds the physical address information because the TAG in physical address get divided into TAG and line offset in cache address. Valid bit tells status of blocks. If it is 1 then data blocks are referred by CPI else not.

7 0

3 years ago