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3 years ago

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Which ordered pair is the solution to the system of linear equations -5x+y=26 and 2x-7y=16

1 answer:

garri49 [273]3 years ago

5 0

Use the elimination method.
(-5x + y = 26)7
2x - 7y = 16

-35x + 7y = 182
2x - 7y = 16

-33x = 198
x = -6

Substitiute -6 for x in one of the equations.
2x -7y = 16
2(-6) - 7y = 16
-12 - 7y =16
-7y = 28
y = -4

The ordered pair would be (-6,-4)

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The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

3 years ago

Evaluate the expression

PolarNik [594]

$\frac{16^{6/4}}{16^{2/2} }$

$\frac{64}{16}$

$4$

7 0

3 years ago

Are these parallelograms congruent?<br> 4 cm<br> 6 cm<br> 6 cm<br> 9 cm<br> yes<br> no

lianna [129]

Answer:

Step-by-step explanation:

Yes 6 over 9 simplifys to 2 over 3.

And 4 over 6 simplifys down to 2 over 3

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7 0

3 years ago

irinina [24]

Answer:

the answer is 28

Step-by-step explanation:

345÷12=28.75

you can't have a 0.75 shirt

7 0

3 years ago

Read 2 more answers

Quickly helllllpppp! plz

xz_007 [3.2K]

Answer:

≈ 8.07 mg

Step-by-step explanation:

Given

f(x) = 12 $(0.82)^{x}$

Substitute x = 1 into f(x) , that is

f(2) = 12(0.82)² = 12 ×0.6724 ≈ 8.07 mg

7 0

3 years ago