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Fed [463]
4 years ago
12

How is the area of a semicircle found?

Mathematics
1 answer:
fenix001 [56]4 years ago
5 0

Answer:

(A) Take half the area of the whole circle.

Step-by-step explanation:

A semi-circle is half of a circle, thus the area of circle is given by:'

Area of circle={\pi}r^2, where r is the radius of the circle.

Since, A semi-circle is half of a circle, therefore area of the semi circle is also half of the circle, therefore

Area of semi circle=\frac{{\pi}r^{2}}{2}

Thus, the area of the semi circle can be found by taking half the area of the whole circle.

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If a menu has a choice of 4 appetizers, 5 main courses, and 5 desserts, how many dinners are possible if each includes one appet
emmasim [6.3K]
Only 4 dinners are possible.
3 0
3 years ago
X+3y=6 and 4x-2y=32 Solve each system of equations
Setler79 [48]

Answer:

x = 54/7 y= -4/7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Simplify: X^-3/x^0<br><br> (Trying to get more characters)
scZoUnD [109]

Answer:

1 / x^3

I don't know what you mean by trying to get more characters by the way sorry.

Step-by-step explanation:

Exponents rule will change X^-3 / x^0 to x^-3-0

Subtract the exponents to get x^-3

Since exponents cannot be negative, the answer will be changed to a fraction 1/x^3.

5 0
3 years ago
QUESTION 1 Evaluate −30 ÷ −6. a 5 b −5 c 6 d −6 QUESTION 2 Evaluate 62 ÷ (3 + 9). a3 b4 c12 d21 QUESTION 3 Danny made a mistake
Mashcka [7]

Answer:

A; ?; Line 3

Step-by-step explanation:

Question 1:

-30 divided by -6 is 5.

The negatives cancel each other out.

And 30 divided by 6 is simply 5.

Question 2:

62\div(3+9)

Do the operation inside the parenthesis first:

62\div12

Divide. 12 does not go into 62 evenly. 12 times 5 is 60, so the answer is 5 remainder 2:

62\div12=5\text { R}2

Or in fractions:

31/6

(Was there a typo? From what you've given me, the correct answer is not listed.)

Question 3:

So we have to following steps:

\text{Line 1: } 21+35\div7+6(2)\\\text{Line 2: }21+5+6(2)\\\text{Line 3: }21+11(2)\\\text{Line 4: }21+22\\\text{Line 5: }43

The mistake is in Line 3. Danny cannot just combine 5+6(2) into 11(2). Instead, he should multiply 6(2) and then add. Thus, the correct solution is:

\text{Line 1: } 21+35\div7+6(2)\\\text{Line 2: }21+5+6(2)\\\text{Line 3: }21+5+12\\\text{Line 4: }26+12\\\text{Line 5: }38

3 0
3 years ago
Chris has twice as many $1 bills as
hodyreva [135]
There is not enough information to give a numerical answer.
Let t=number of ten dollar bills.
"he has twice as many dimes as he has 10 dollar bills", so the amount A is
A=10*t+0.1*(2t)
"he has twice as many pennies as he has dimes"
A=10*t+0.1*(2t)+0.01*4t
"chris has twice as many 1 dollar bills as pennies"
A=10*(t)+0.1*(2t)+0.01*(4t)+1*(8t)
=18.24t
Therefore the total amount Chris has is 18.24 times the number of $10 bills he possesses.
3 0
3 years ago
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