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Fed [463]
3 years ago
12

How is the area of a semicircle found?

Mathematics
1 answer:
fenix001 [56]3 years ago
5 0

Answer:

(A) Take half the area of the whole circle.

Step-by-step explanation:

A semi-circle is half of a circle, thus the area of circle is given by:'

Area of circle={\pi}r^2, where r is the radius of the circle.

Since, A semi-circle is half of a circle, therefore area of the semi circle is also half of the circle, therefore

Area of semi circle=\frac{{\pi}r^{2}}{2}

Thus, the area of the semi circle can be found by taking half the area of the whole circle.

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A board is 60.96 centimeters long. How long is the board in inches?
krok68 [10]

Answer:

24.02 inches

Step-by-step explanation:

\because \: 1 \: cm = 0.394 \: inch \\  \therefore \: 60.96 \: cm = 60.96 \times 0.394 \: in \\  = 24.01824 \\  = 24.02 \: in

Thus, board is 24.02 inches long.

7 0
3 years ago
Read 2 more answers
I NEED HELP ASAP 6th GRD WORK HELPPP
tatuchka [14]

Answer:

28cm

Step-by-step explanation:

A=a+b

2h=4+10

2·4=  28cm

3 0
3 years ago
I NEED HELP ASAP PLEASE SOLVE FOR X
Marina CMI [18]
ANSWER: x = 130°

EXPLANATION: You must add given angles and then subtract from 180°.
8 0
2 years ago
Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time
kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0
3 years ago
What is 2/100000 as a decimal
blsea [12.9K]
2.0e-6
Is the answer to your question

6 0
3 years ago
Read 2 more answers
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