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Fantom [35]
3 years ago
10

What is the answer to 50-43+(6x8)-9+3 and how do you solve it?

Mathematics
2 answers:
adell [148]3 years ago
8 0

Answer:

Hey there!

50-43+(6x8)-9+3

50-43+48-9+3

7+48-9+3

46+3

49

Let me know if this helps :)

Elden [556K]3 years ago
4 0

Answer:

= 49

Step-by-step explanation:

  50-43+(6x8)-9+3

=  50 - 43 + (48) - 9 + 3

=  (50 + 48 + 3) + (-43 - 9)

= 101 - 52

= 49

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player A led a baseball league in runs batted in for the 2006 regular season. player B. who came in second player to A, had 13 f
Alla [95]
A= player A runs batted in
b= player B runs batted in= a-13

250= a + b
substitute b= a-13 for b

250= a + (a-13)
combine like terms
250= 2a -13
add 13 to both sides
263= 2a
divide both sides by 2
131.5= a

Substitute a= 131.5 into equation
250= a + b
250= 131.5 + b
subtract 131.5 from both sides
118.5= b

Hope this helps! :)
7 0
2 years ago
Mary drove 303 miles in 15 gallons of gas at this rate how many miles would she drive using 16 gallons of gas
Rainbow [258]
324 because if you do 303/15 it’s 20.2 then you add that to 303 which is 323.2 but you can’t have .2 of a gallon so it’s 324
4 0
3 years ago
Please help I need help
navik [9.2K]

Answer:

L=10pi, or 31.42

Step-by-step explanation:

4 0
2 years ago
11^2^3x=983298f+0220.2^2(38) <br> whats x.
Mazyrski [523]

Answer:

x=1638831.492383738758729e+23f+0

Step-by-step explanation:

(1123)(x)=983298f+(220.22)(38)

Step 1: Divide both sides by 8.954302432552374e+23.

8.954302432552374e+23x

8.954302432552374e+23

=

983298f+1842545.52

8.954302432552374e+23

x=

163883

1.492383738758729e+23

f+0

6 0
2 years ago
Read 2 more answers
Can someone PLEASE help me with Trigonometry???
Svetach [21]
\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\&#10;-------------------------------\\\\&#10;sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}&#10;\\\\\\&#10;sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)&#10;\\\\\\&#10;\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}

but anyway, the numerator will give the angles, and θ is just half of each

\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\&#10;-------------------------------\\\\&#10;sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}&#10;\\\\\\&#10;sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o&#10;\\\\\\&#10;\theta=\cfrac{-8.05}{2}\implies \theta=-4.025

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there
7 0
3 years ago
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