Question

If a2 + b2 = 11 how much is b2

Answer 1

the Pythagorean Theoremproof of let ΔABC be a right triangle. and sinA=a/c, and cosA= b/ca opposite side of the angle Ab the adjacent side of the angle Aand c is the hypotenuswe know that  sin²A +cos²A= (a/c)²+ (b/c) ², but  sin²A +cos²A=1so,  a²/c²+ b²/c ²=1 which implies  a²+ b²=c² the answer is Transitive Property of Equality proof the right triangles BDC and CDA are siWe start with the original right triangle, now denoted ABC, and need only one additional construct - the altitude AD. The triangles ABC, DBA, and DAC are similar which leads to two ratios:AB/BC = BD/AB and AC/BC = DC/AC.Written another way these becomeAB·AB = BD·BC and AC·AC = DC·BCSumming up we getAB·AB + AC·AC= BD·BC + DC·BC                          = (BD+DC)·BC = BC·BC.so not in the proof is Transitive Property of Equality

Answer 2

The answer is 5.5 bevaise we dont know what a2 is and if you cut it in half between bother the answer is 5.5