3 years ago

Geometry Chapter 4 Practice Test

Mathematics

1 answer:

kumpel [21]3 years ago

8 0

yasssssss, where are the math problems?

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3+-1/1/3 the first half is 3+-1 the second half is 1/3

kolbaska11 [484]

$\bf \cfrac{3\pm1}{\frac{1}{3}}\implies 
\begin{cases}
\cfrac{3+1}{\frac{1}{3}}\\\\
\cfrac{3-1}{\frac{1}{3}}
\end{cases}\\\\
-------------------------------\\\\$

$\bf \cfrac{3+1}{\frac{1}{3}}\implies \cfrac{4}{\frac{1}{3}}\implies \cfrac{\frac{4}{1}}{\frac{1}{3}}\implies \cfrac{4}{1}\cdot \cfrac{3}{1}\implies \cfrac{4\cdot 3}{1\cdot 1}\implies \cfrac{12}{1}\implies \boxed{12}
\\\\\\
\cfrac{3-1}{\frac{1}{3}}\implies \cfrac{2}{\frac{1}{3}}\implies \cfrac{\frac{2}{1}}{\frac{1}{3}}\implies \cfrac{2}{1}\cdot \cfrac{3}{1}\implies \cfrac{2\cdot 3}{1\cdot 1}\implies \cfrac{6}{1}\implies \boxed{6}$

6 0

3 years ago

If h(x)= (f o g)(x) and h(x)= 4 √x+7, find g(x) if f(x) = 4 √x+1

stepladder [879]