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3 years ago

How many numbers lie between the square of 56 and 57

Mathematics

2 answers:

NARA [144]3 years ago

7 0

Answer:

Given, two numbers 56 and 57 we need to find out the numbers lie between the squares of the given numbers.

Now, we have numbers lying between the square of n and (n + 1) is 2n

⇒ Numbers between squares of 56 and (56 + 1) = 2 × 56 = 112

Hence, 112 numbers lies between the square of the given numbers.

uysha [10]3 years ago

5 0

<h2>Answer:</h2>

112

<h2>Step-by-step explanation:</h2>

Given, two numbers 56 and 57 we need to find out the numbers lie between the squares of the given numbers. Now, we have numbers lying between the square of n and (n + 1) is 2n. ⇒ Numbers between squares of 56 and (56 + 1) = 2 × 56 = 112. Hence, 112 numbers lies between the square of the given numbers.

<h2>#CarryOnLearning</h2><h2>#BrainliestAnswer</h2><h2>#Brainliest</h2>

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Three friends were born in consecutive years. The some of their birth years is 5982.find the year in which each person was born

posledela

A+b+c=5982
find the average of the three friends
5982/3=1994
add and subtract one to find the average
1994+1=1995
1994-1=1993
add all the years together to check
1993+1994+1995=5983

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3 years ago

The length of a rectangle is 2 meters less than 2 times the width. The perimeter is 20 meters. Find the width.

kakasveta [241]

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3 years ago

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77julia77 [94]

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Step-by-step explanation:

3.281 feet makes 1 meter

To solve the question, Multiply the value by 3.281:

100 meters = 100 x 3.281 feets

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3 years ago

A function follows the rule y = -75 - 5 x . When the function's output is 25, the equation is 25 = -75 - 5 x .

zhenek [66]

Answer:

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Step-by-step explanation:

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3 years ago

Lydia graphed ΔDEF at the coordinates D (−2, −1), E (−2, 2), and F (0, 0). She thinks ΔDEF is a right triangle. Is Lydia's asser

alukav5142 [94]

Answer:

No; the slopes of segment EF and segment DF are not opposite reciprocals.

Step-by-step explanation:

The slope between two points O(e, f) and X (g,h) is given as:

$slope\ of\ |OX|=\frac{h-f}{g-e}$

The slopes of segment EF and segment DF are given below:

$slope\ of\ |EF|=\frac{0-2}{0-(-2)}=-1\\\\slope\ of\ |DF|=\frac{0-(-2)}{0-(-1)}=2\\$

For triangle DEF to be a right triangle, DF and EF are supposed to be perpendicular to each other. Two line are said to be perpendicular if the product of their slope is -1, i.e the slope of one line is the negative reciprocal (opposite reciprocal) of the other line.

Since the slope of DF and EF are not opposite reciprocals, ΔDEF is not a right triangle.

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3 years ago