Answer: Where are the lines?
Answer:
T(t) = 3sin((t-5)π/30)
Step-by-step explanation:
5 minutes after Thomas ties it on, the torque is zero and increasing. So, the sine function is shifted right 5 minutes. The maximum value is 3, so that is the multiplier of the sine function. The period is 60 minutes, so the coefficient of t is (2π/60) = π/30. The function you want is ...
T(t) = 3sin((t-5)π/30)
Answer:
slope = 3, point = (6, -2)
Step-by-step explanation:
This is in point-slope form which looks like this : y-y1 = m(x-x1).
m is the slope, an x1 and y1 are the x and y coordinates of the point. Remember to flip the sign of the numbers for the points i.e. the y+2 in the equation becomes -2 for the point.
9514 1404 393
Answer:
- sin(Ф) = (4/41)√41; csc(Ф) = (√41)/4
- cos(Ф) = (5/41)√41; sec(Ф) = (√41)/5
- tan(Ф) = 4/5; cot(Ф) = 5/4
Step-by-step explanation:
The mnemonic SOH CAH TOA can help you with three of the functions. Then you need to remember the relations between those and the other three.
Tan = Opposite/Adjacent
tan(Ф) = 4/5
This suggests you can draw a triangle like the one attached that has adjacent side 5 and opposite side 4. Then hypotenuse can be found from the Pythagorean theorem:
AC² = AB² +BC² = 5² +4² = 41
AC = √41 . . . . . hypotenuse
Then the other trig functions are ...
Sin = Opposite/Hypotenuse
sin(Ф) = 4/√41 = (4/41)√41
Cos = Adjacent/Hypotenuse
cos(Ф) = 5/√41 = (5/41)√41
And the reciprocal functions are ...
csc(Ф) = 1/sin(Ф) = (√41)/4
sec(Ф) = 1/cos(Ф) = (√41)/5
cot(Ф) = 1/tan(Ф) = 5/4
Answer:
If he has 45% of his cheak remaining we already have the remaining so we just to turn it into a fraction
First we put it over 100
<u>45</u>
100
Then we reduce it to the lowest terms
which would be
9/20