Find the area and perimeter of the shaded region. Stuck on this one can someone help me
2 answers:
Answer:
perimeter-
perimeter outer rectangle = 2 (l+b)
=2×8+9
= 2×17
2×17 =34 cm sq.
perimeter of inner rectangle = 2 (l+b)
= 2×5+3
=2× 8
= 16 cm sq.
perimeter of shaded portion= 34 - 16
= 18 cm sq.
area-
<em>area</em><em> </em><em>of</em><em> </em><em> </em><em>inner</em><em> </em> rectangle =l×b
l×b = 3×5
3×5=15
15 cm sq.
area of outer rectangle =l×b
l×b= 9×8
9×8= 72
72 cm sq.
area of shaded portion = 72 -15 =57 cm sq.
hey there! In second method i have done first area of inner rectangle but you have to do first area of outer rectangle...
hope it helps you....
Answer:
Let A1 = be the large rectangle and A2 the small rectangle
=> Area A1: S1 = a1.b1 => S1 = 8 x 9 = 72m2
=> Area A2: S2 = a2.b2 => S2 = 3 x 5 = 15 m2
=> Area of the remaining surrounding square: S1-S2 = 72-15 = 67m2
=> Perimeter A1: P1 = 2 (a1 + b1) = 2 (9 + 8) = 34m
=> Perimeter A2: P2 = 2 (a2 + b2) = 2 (3 + 5) = 16m
=> Perimeter of the surrounding square: P1-P2 = 34-16 = 18m
Step-by-step explanation:
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