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2 years ago

Find the area and perimeter of the shaded region. Stuck on this one can someone help me

Mathematics

2 answers:

alekssr [168]2 years ago

3 0

Answer:

perimeter-

perimeter outer rectangle = 2 (l+b)

=2×8+9

= 2×17

2×17 =34 cm sq.

perimeter of inner rectangle = 2 (l+b)

= 2×5+3

=2× 8

= 16 cm sq.

perimeter of shaded portion= 34 - 16

= 18 cm sq.

area-

area of inner rectangle =l×b

l×b = 3×5

3×5=15

15 cm sq.

area of outer rectangle =l×b

l×b= 9×8

9×8= 72

72 cm sq.

area of shaded portion = 72 -15 =57 cm sq.

hey there! In second method i have done first area of inner rectangle but you have to do first area of outer rectangle...

hope it helps you....

wel2 years ago

3 0

Answer:

Let A1 = be the large rectangle and A2 the small rectangle

=> Area A1: S1 = a1.b1 => S1 = 8 x 9 = 72m2

=> Area A2: S2 = a2.b2 => S2 = 3 x 5 = 15 m2

=> Area of the remaining surrounding square: S1-S2 = 72-15 = 67m2

=> Perimeter A1: P1 = 2 (a1 + b1) = 2 (9 + 8) = 34m

=> Perimeter A2: P2 = 2 (a2 + b2) = 2 (3 + 5) = 16m

=> Perimeter of the surrounding square: P1-P2 = 34-16 = 18m

Step-by-step explanation:

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2 years ago

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34kurt

Answer:

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Step-by-step explanation:

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2 years ago

A right square pyramid with base edges of length $8\sqrt{2}$ units each and slant edges of length 10 units each is cut by a plan

seropon [69]

Answer:

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Step-by-step explanation:

Given:

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$\sqrt{10^{2 - (4\sqrt{2} ^{2} }) }$ = $\sqrt{100 - 32}$ = $\sqrt{68}$ units

One again, you can use Pythagoras again to get the perpendicular height of the entire pyramid.

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Because slant edges of length 10 units each is cut by a plane that is parallel to its base and 3 units above its base. So we have the other dementions of the small right square pyramid:

The height 3 units
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3 years ago

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Sindrei [870]

Answer:

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