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erma4kov [3.2K]
3 years ago
12

W/2 - 12 = -8 What is w ? Oof explain this to me I'm confused

Mathematics
1 answer:
lbvjy [14]3 years ago
7 0

Answer:

w = 8

Step-by-step explanation:

w/2 - 12 = -8

Add 12 to each side

w/2 - 12+12 = -8+12

w/2 = 4

Multiply each side by 2

w/2*2 = 4*2

w = 8

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The values that make the denominator zero are not in the domain.

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3 years ago
the figure below shows a circle centre of radius 10 cm the chord PQ=16cm calculate the area of the shaded region​
m_a_m_a [10]

Step-by-step explanation:

OPQ originally forms a sector, the formula for sector is

\frac{x}{360} \pi {r}^{2}

where x is the degrees of rotation between the two radii.

We know three sides length and is trying to find an angle between the radii so we can use law of cosines which states that

16 =  \sqrt{10 {}^{2} + 10 {}^{2}   - 2(100) \times  \cos(o) }

This isn't the standard formula, it's for this problem

16 =  \sqrt{200 - 200 \times  \cos(o) }

16 =  \sqrt{200  - 200 \cos(o) }

256 = 200 - 200 \cos(o)

56 =  - 200 \cos(o)

-  \frac{7}{25}  =  \cos(o)

\cos {}^{ - 1} (  - \frac{7}{25} )  =  \cos {}^{ - 1} ( \cos(o) )

106.26 = o

So we found our angle of rotation, which is 106.26

Now, we do the sector formula.

\frac{106.26}{360} (100)\pi

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is the area of sector.

Now let find the area of triangle, we can use Heron formula,

The area of a triangle is

\sqrt{s(s - a)(s - b)(s - c)}

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Which is

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\sqrt{(36)(64)}

6  \times 8 = 48

So our area of the triangle is 48. Now, to find the shaded area subtract the main area,( the sector of the circle) by the area of the triangle so we get

\frac{10626}{360}  - 48

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44.73

6 0
2 years ago
The square tile has an area of 324 square inches. What is the perimeter
solniwko [45]
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Hope this helps.
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