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balu736 [363]
3 years ago
14

Which benchmark is between 3/7 and 16/20 Answers between 1/2 and 1 whole?

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0

Answer:

140

Step-by-step explanation:

I think you mean "lowest common denominator" where you use the word "benchmark."

The LCD of 3/7 and 16/20 is 140; 140 is the smallest number evenly divisible by both 7 and 20.

Then 3/7 → 60/140 and 16/20 → 112/140.   112/140 is between 1/2 and 1.

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What is the center of a circle whose equation is x2 + y2 + 4x – 8y + 11 = 0?
Valentin [98]

Answer:

Step-by-step explanation:

eq. of circle is x²+y²+2gx+2fy+c=0

center=(-g,-k)

given eq. is x²+y²+4x-8y+11=0

comparing

2gx=4x

g=2

2fy=-8y

f=-4

center=(-2,4)

7 0
3 years ago
Which statement best describes a secant of a circle? (1 point) It is a line that touches only one point on the circle. It is a l
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8 0
4 years ago
Read 2 more answers
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shutvik [7]

Answer:

Lines e & f are parallel to eachother and lines g & h are parallel to eachother

Step-by-step explanation:

Parallel lines never intersect.

4 0
3 years ago
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8 0
3 years ago
In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
3 years ago
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