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Average acceleration = (173-0)/39=4.44m/s^2
............................,,,;,,...............:......
Answer:

Do not reject 
Step-by-step explanation:
From the question we are told that
Sample size 
Sample size 
Sample proportion 1 
Sample proportion 2 
95% confidence interval
Generally for 95% confidence level
Level of significance


Therefore

Generally the equation for confidence interval between
is mathematically given as





Therefore
Confidence interval is

Conclusion
Given the confidence interval has zero
Therefore do not reject 
9514 1404 393
Answer:
a) P(t) = 6.29e^(0.0241t)
b) P(6) ≈ 7.3 million
c) 10 years
d) 28.8 years
Step-by-step explanation:
a) You have written the equation.
P(t) = 6.29·e^(0.0241·t)
__
b) 2018 is 6 years after 2012.
P(6) = 6.29·e^(0.0241·6) ≈ 7.2686 ≈ 7.3 . . . million
__
c) We want t for ...
8 = 6.29·e^(0.0241t)
ln(8/6.29) = 0.0241t
t = ln(8/6.29)/0.0241 ≈ 9.978 ≈ 10.0 . . . years
__
d) Along the same lines as the calculation in part (c), doubling time is ...
t = ln(2)/0.0241 ≈ 28.7613 ≈ 28.8 . . . years