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Novosadov [1.4K]
3 years ago
5

Can someone please check my answer !!!

Mathematics
2 answers:
Verdich [7]3 years ago
7 0

Answer:

its actually the one on the top right

Step-by-step explanation:

Hope it helps ;)

let me know

Bess [88]3 years ago
7 0
Ur right I think I’m 89% sure ahh
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Find DF AC=600 CB=480 AB=360
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A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Houston. The stud
iris [78.8K]

Answer:

-0.048

Do not reject  H_0:P_1-P_2=0

Step-by-step explanation:

From the question we are told that

Sample size n_1=350

Sample size n_2=250

Sample proportion 1  \hat P= \frac{25}{350} =>0.07

Sample proportion 2 \hat P= \frac{19}{250} =>0.076

95% confidence interval

Generally for 95% confidence level

Level of significance

 \alpha = 1-0.95=>0.05

 \alpha /2=\frac{0.05}{2} =>0.025

Therefore

Z_a_/_2=1.96

Generally the equation for confidence interval between P_1 - P_2  is mathematically given as

(\hat P_1-\hat P_2)\pm Z_a_/_2\sqrt{\frac{\hat P_1(1-\hat P_1)}{n_1}+\frac{\hat P_2(1-\hat P_2)}{n_2}  }

(0.07-0.076)\pm 1.96\sqrt{\frac{0.07(1-0.07)}{350}+\frac{0.076(1-0.076)}{250}  }

(0.07-0.076)\pm 1.96\sqrt{4.66896*10^-^4  }

(-0.006)\pm 0.042

(-0.006)- 0.042=>-0.048

(-0.006)+ 0.042=>0.036

Therefore

Confidence interval is

-0.048

Conclusion

Given the confidence interval has zero

Therefore do not reject  H_0:P_1-P_2=0

6 0
2 years ago
In 2012, the population of a city was 6.29 million. The exponential growth rate was
RoseWind [281]

9514 1404 393

Answer:

  a) P(t) = 6.29e^(0.0241t)

  b) P(6) ≈ 7.3 million

  c) 10 years

  d) 28.8 years

Step-by-step explanation:

a) You have written the equation.

  P(t) = 6.29·e^(0.0241·t)

__

b) 2018 is 6 years after 2012.

  P(6) = 6.29·e^(0.0241·6) ≈ 7.2686 ≈ 7.3 . . . million

__

c) We want t for ...

  8 = 6.29·e^(0.0241t)

  ln(8/6.29) = 0.0241t

  t = ln(8/6.29)/0.0241 ≈ 9.978 ≈ 10.0 . . . years

__

d) Along the same lines as the calculation in part (c), doubling time is ...

  t = ln(2)/0.0241 ≈ 28.7613 ≈ 28.8 . . . years

4 0
3 years ago
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