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3 years ago

The product of two numbers is 12

Mathematics

2 answers:

Maslowich3 years ago

8 0

it could be 1 and 12 2 and 6 3 and 4

Step-by-step explanation:

THe product is the answer to a multiplication equation so the numbers above are all products of 12! :D

Gnoma [55]3 years ago

4 0

Answer:

1x12

2x6

3x4

4x3

6x3

12x1

Step-by-step explanation:

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Step-by-step explanation:

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Someone please help me

SOVA2 [1]

Gosh, when I saw that my mind went blank

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3 years ago

Consider the equation a(3 - x) = - 2x + b. What values of a and b make the solution of the equation x =-2? Write a number from t

-Dominant- [34]

Answer:

a=1, b=1

Step-by-step explanation:

Given the equation: $a(3 - x) = - 2x + b$

If the solution of the equation $x=-2$

Then to find the values of a and b, we substitute $x=-2$ into the equation.

$a(3 - x) = - 2x + b\\a(3 - (-2)) = - 2(-2) + b\\a(3+2)=4+b\\5a=4+b\\5a-b=4\\$If we make the substitution a=1, b=1 into the above equation\\5(1)-1=4 is true.\\Therefore: a=1, b=1$

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3 years ago

The length of a rectangle is 5m less than three times the width, and the area of the rectangle is 50m^(2). Find the dimensions o

Ilia_Sergeevich [38]

Answer:

The width is 5m and the length is 10m.

Step-by-step explanation:

Rectangle:

Has two dimensions: Width(w) and length(l).

It's area is:

$A = w*l$

The length of a rectangle is 5m less than three times the width

This means that $l = 3w - 5$

The area of the rectangle is 50m^(2)

This means that $A = 50$ . So

$A = w*l$

$50 = w*(3w - 5)$

$3w^{2} - 5w - 50 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$3w^{2} - 5w - 50 = 0$

$a = 3, b = -5, c = -50$

$\bigtriangleup = (-5)^{2} - 4*3*(-50) = 625$

$w_{1} = \frac{-(-5) + \sqrt{625}}{2*3} = 5$

$w_{2} = \frac{-(-5) - \sqrt{625}}{2*3} = -3.33$

Dimension must be positive result, so

The width is 5m(in meters because the area is in square meters).

Length:

$l = 3w - 5 = 3*5 - 5 = 10$

The length is 10 meters

6 0

3 years ago