Answer:
$3,623.84 Exact answer without rounding | $3,623.85 ~ (Approximent Answer with rounding.)
Step-by-step explanation:
Compound Interest Has a Specific Formula:
This case is Exponential Growth.
Formula: y= ab^x
You need to set up the equation.
First we need to define the rate of growth meaning what do you have to do for the 6.5%.
You need to do 100% + 6.5% = 106.5%
You need to convert the percent to a decimal which will be 1.065
Now we need to start plugging things into our formula to solve.
Your initial Starting amount was $3000
So you need to have y=3000(b)^x
We now know that the rate of growth is 1.065 so the b would be 1.065
y=3000(1.065)^x
Our power to x is our 3.5 years.
Our Equation now:
y=3000(1.065)^3
Now you need to use a calculator to do this due to the amount of decimals and digits.
Remember pemdas when doing this!!!
The answer should result to $3,623.84 but if rounded then: $3,623.85
Answer:
The distance of the park from the Gary's house is 125 miles.
Step-by-step explanation:
Speed of Gary = 50 miles/hour
Time taken by Gary to reach the park from his house = 2.5 hours
Now, we know that,
Distance travelled = speed × time
So, distance between park and Gary's house = speed × time
= 50 × 2.5
= 125 miles
So, the park is 125 miles away from the Gary's house.
Answer:
Indeed
Step-by-step explanation:
Answer:
B). graph of increasing exponential function going through point (0, 3)
Step-by-step explanation:
Given function is 
Now we need to find about which of the given choices best describes the given function. Where given choices are:
A). graph of increasing exponential function going through point 0, 2
B). graph of increasing exponential function going through point 0, 3
C). graph of increasing exponential function going through point 0, 1
D). graph of increasing exponential function going through point 0, 4
plug x=0 into given function
Hence graph passes through point (0,3).
growth factor 1.5 is greater than 1 so that means it is increasing function.
Hence correct choice is:
B). graph of increasing exponential function going through point (0, 3)
