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Kay [80]
3 years ago
7

A commuter has to cross a train track each day on the way to work. The probability of having to wait for a train is .2. If she h

as to wait for a train, her commute takes 25 minutes; otherwise, it takes 20 minutes. What is her expected commute time?
Mathematics
1 answer:
Anni [7]3 years ago
7 0

Answer:

21 minutes

Step-by-step explanation:

Her expected commute time is given by the probability of having to wait for the train (0.2) multiplied by the commute time in this scenario (25 min), added to the probability of not having to wait for the train (1 - 0.2) multiplied by the commute time in this scenario (20 min). The expected commute time is:

E(X) = 0.2*25+(1-0.2)*20\\E(X) = 21\ minutes

Her expected commute time is 21 minutes.

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Idk how to solve this
Mnenie [13.5K]

Answer:

18.2222222222 mph

Step-by-step explanation:

82 x 4.5 = 18.222222222

3 0
3 years ago
Read 2 more answers
If a statement is true, then it’s converse must be true as well. True or false
TEA [102]
Answer: true


Explanation: because if a statement is true then it’s convert
5 0
3 years ago
Which ordered pair is a solution of the equation? 2x+4y=6x-y OPTION A: Only (4,5) OPTION B: Only (5,4) OPTION C Both A and B OPT
sammy [17]

Answer:

option b

Step-by-step explanation:

replace x and y with the x and y of the ordered pair

option a: 2(4)+4(5)=6(4)-5

solve

8+20=24-5

28=19  not true

option b:2(5)+4(4)=6(5)-4

solve

10+16=30-4

26=26  true

6 0
4 years ago
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
Kevin has just purchased a small rectangular fish tank that holds 904.5 milliliters of water. The tank has a length of 15 cm and
Nitella [24]

Answer:

A stone is thrown straight up from the edge of a roof, 750 feet above the ground at a speed of 14 feet per second. A) Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 2 seconds later? B) At what time does the stone hit the ground? C) What is the velocity of the stone when it hits the ground?

Step-by-step explanation:

A stone is thrown straight up from the edge of a roof, 750 feet above the ground at a speed of 14 feet per second. A) Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 2 seconds later? B) At what time does the stone hit the ground? C) What is the velocity of the stone when it hits the ground?

5 0
3 years ago
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