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UkoKoshka [18]
3 years ago
10

when making pink paint, the art teacher uses the ratio 3:2. For every 3 cups of white paint she used in the mixture, she needs t

o use 2 cups of red paint.
Mathematics
1 answer:
Vlad [161]3 years ago
7 0
Whats the question ??
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Tristan records the number of customers who visit the store each hour on a Saturday. His data representing the first seven hours
Alona [7]

Answer:

Option C is correct.

Step-by-step explanation:

We have been given total 8 data

Data is : 12,15,18,20,23,23,28

Here, n=7

Median is \frac{n+1}{2}=\frac{7+1}{2}=4th term

Median is 20.

When one data is added n=8

The median of  even number of data is  

median=\frac{\frac{n}{2}\text{th and}\frac{n}{2}+1\text{th}}{2}

Median is \frac{8}{2}\text{th and}\frac{8}{2}+1th

Median is 4\text{th and}5th

4th terms is 20

5th terms is 23

Since, median should not be change hence,

Median will be 20.

Therefore, option C is correct.

6 0
3 years ago
Read 2 more answers
Simplify the numerical expression: -4.2 + 8.1 x ( -1.9)
SIZIF [17.4K]
-19.59 is your answer because u do PEMDAS and that would be 8.1*(-1.9) which gives you -15.39 Then you do -4.2+-15.39 and you would get -19.59
3 0
3 years ago
What is the surface area of the cylinder with height 2 yd and radius 3 yd? Round your answer to the nearest thousandth.
olasank [31]
<h2>Given :</h2>

  • height (h) = 2 yd

  • radius (r) = 3 yd

<h2>Solution :</h2>

\boxed{ \mathrm{Surface \:  Area = 2\pi r(h +r )}}

  • 2 \times 3.14 \times 3 \times (3 + 2)

  • 18.84 \times 5

  • \boxed{\mathrm{94.2 \: yd {}^{2} }}

_____________________________

\mathrm{ \#TeeNForeveR}

3 0
3 years ago
Question 5 and 6 please help me
sp2606 [1]

Problem 5

The function is continuous for the given domain x \ge 6

This is because y = (-5/6)x+5 is itself continuous, and any interval subset of this function is also continuous. We can plug in any real number that is equal to 6 or larger, and get some y output. If we plugged in x = 6, then we'd get

y = (-5/6)x+5

y = (-5/6)*6 + 5

y = -5+5

y = 0

This is the largest y value possible. Why? Because y = (-5/6)x+5 has a negative slope, so the graph is going downhill as you read it from left to right. As x gets bigger, y gets smaller. The smallest x value allowed in the domain produces the largest y value in the range. There is no smallest y value as the y values keep going down forever.

The range is therefore y \le 0

In interval notation, you can write the range as (-\infty, 0]. The square bracket indicates "include this endpoint as part of the range".

======================================================

Problem 6

The function is discrete for this given domain. The domain itself is a discrete list of values. We cannot plug in values between say 0 and 2. We can only substitute one of those values from the list given. Consequently, the y values will also be a list, and not an interval like problem 5 had.

-----------

If you plugged in x = -4, then you should get...

y = (-1/2)*(-4)+2

y = 2+2

y = 4

So the input x = -4 lead the output y = 4

Repeat for x = -2

y = (-1/2)x+2

y = (-1/2)*(-2)+2

y = 1+2

y = 3

and the same for x = 0 as well

y = (-1/2)x+2

y = (-1/2)*0 + 2

y = 0 + 2

y = 2

and x = 2 also

y = (-1/2)x+2

y = (-1/2)*2 + 2

y = -1+2

y = 1

Finally, plug in x = 4

y = (-1/2)x+2

y = (-1/2)*4+2

y = -2+2

y = 0

---------------

If we plugged each of these x values {-4, -2, 0, 2, 4} one at a time into the equation y = (-1/2)x+2, then we get this list of values {4, 3, 2, 1, 0}

Sorting the values from smallest to largest, we have this range {0, 1, 2, 3, 4}

3 0
3 years ago
A semicircle is attached to the side of a rectangle as shown.
laiz [17]

Answer:

58.8\ mm^2

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of semicircle

step 1

Find the area of rectangle

The area of rectangle is equal to

A=bh

where

b=9\ mm\\h=3\ mm

substitute

A=(9)(3)=27\ mm^2

step 2

Find the area of semicircle

The area of semicircle is equal to

A=\frac{1}{2}\pi r^{2}

we have

r=9/2=4.5\ mm ---> the radius is half the diameter

\pi =3.14

substitute

A=\frac{1}{2}(3.14) (4.5)^{2}

A=31.8\ mm^2

step 3

Find the area of the figure

A=27+31.8=58.8\ mm^2

4 0
4 years ago
Read 2 more answers
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