The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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Answer:
Step-by-step explanation::)
Answer:
3 c ock
Step-by-step explanation:
Reason being of you add 1 c ock and 2 c ock you get 3 c ock
Answer:
answer below
Step-by-step explanation:
a is: 0.8
b is : 2
c is: 5
d is: 12.5
Answer:
log₅(3125) = 5
Step-by-step explanation:
Given:
log₅(3125)
Now,
using the property of log function that
logₐ(b) = 
thus,
Therefore, applying the above property, we get
⇒ 
(here log = log base 10)
now,
3125 = 5⁵
thus,
⇒ 
Now,
we know from the properties of log function that
log(aᵇ) = b × log(a)
therefore applying the above property we get
⇒ 
or
⇒ 5
Hence,
log₅(3125) = 5
