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Umnica [9.8K]
3 years ago
6

Answer if you know DO NOT COPY OTHER PEOPLE PLS

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0
Okay so...
There are 21 groups of 3.
21 x 3 = 63.
63 people are in the room.
Vilka [71]3 years ago
7 0

Answer: 63 because 21 times 3 = 63

Step-by-step explanation:

There are 63, it can't be 7 because why would there be 7 students in 21 groups, so 21 times 3 equals 63

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N-6 divided by 3 = -4 what is n
puteri [66]
-6 is the answer that you want
8 0
3 years ago
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Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Together, Rhonda and Margo saved $478.50. If Rhonda saved $225 of that total, how much did Margo save? Select the addition equat
Sav [38]

Answer:

$253.5

Step-by-step explanation:

Total amount saved = Amount Rhonda saved + Amount Margo saved

= $478.50 − $225

Amount Margo saved = $253.5

3 0
3 years ago
PLEASE HELP ANYONE.....
irga5000 [103]

Answer:

the awnser should have is. b

8 0
3 years ago
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What is the result when 75,069 is divided by 45
Lera25 [3.4K]

Answer: 1668.2

Multiply 1668.2×45 and get 75,069

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