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3 years ago

How do polynomial identities apply to complex numbers?

Mathematics

1 answer:

Leni [432]3 years ago

3 0

Answer:

Let start with what a polynomial is. Look in the step-by-step explanation.

Step-by-step explanation:

We know a polynomial has more than one term, right?

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Give one pair of vertical angles and one pair of supplementary angles shown in the figure below.

vichka [17]

Answer:

Vertical : Angles 1 & 4 Supplementary: 5 & 6

Step-by-step explanation:

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3 years ago

Verify the identity. 4 csc 2x = 2 csc2x tan x

vlada-n [284]

Step-by-step explanation:

$4csc(2x) = 2csc^2(x) tan(x)$

We start with Left hand side

We know that csc(x) = 1/ sin(x)

So csc(2x) is replaced by 1/sin(2x)

$4 \frac{1}{sin(2x)}$

Also we use identity

sin(2x) = 2 sin(x) cos(x)

$4 \frac{1}{2sin(x)cos(x)}$

4 divide by 2 is 2

Now we multiply top and bottom by sin(x) because we need tan(x) in our answer

$2\frac{1*sin(x)}{sin(x)cos(x)*sin(x)}$

$2\frac{sin(x)}{sin^2(x)cos(x)}$

$2\frac{1}{sin^2(x)} \frac{sin(x)}{cos(x)}$

We know that sinx/ cosx = tan(x)

Also 1/ sin(x)= csc(x)

so it becomes 2csc^2(x) tan(x) , Right hand side

Hence verified

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