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4 years ago

CAN YOU PLEASEEE HELP ME IM DESPERATE AND NEED THE ANSWER ASAP

Mathematics

1 answer:

Juliette [100K]4 years ago

6 0

Answer:

6(x-3)(X^2+4)(x+1)=0

real answers:

(x-3)=0

x=3

x+1=0

x=-1

This numbers are not real:

x^2+4=0

x^2=-4

$\sqrt{x}$ = ± $\sqrt{2}$

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Is 9r+16=5 a literal equation? Explain.

Butoxors [25]

This is not a literal equation but you can divide 3.14 divide by 5

Step-by-step explanation:

5 0

3 years ago

1/5 (4-3x) = 1/7 (3x - 4) pls solve

natulia [17]

$\huge \boxed{\mathfrak{Question} \downarrow}$

$\large\sf\frac{1}{5} (4 - 3x) = \frac{1}{7} (3x - 4) \\$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\frac{1}{5} (4 - 3x) = \frac{1}{7} (3x - 4) \\$

Use the distributive property to multiply 1/5 by 4-3x.

$\frac{1}{5}\times 4+\frac{1}{5}\left(-3\right)x=\frac{1}{7}\left(3x-4\right) \\$

Multiply 1/5 and 4 to get 4/5.

$\frac{4}{5}+\frac{1}{5}\left(-3\right)x=\frac{1}{7}\left(3x-4\right) \\$

Multiply 1/5 and -3 to get -3/5.

$\frac{4}{5}+\frac{-3}{5}x=\frac{1}{7}\left(3x-4\right) \\$

Use the distributive property to multiply 1/7 by 3x-4.

$\frac{4}{5}-\frac{3}{5}x=\frac{1}{7}\times 3x+\frac{1}{7}\left(-4\right) \\$

Multiply 1/7 and 3 to get 3/7 & 1/7 × -4 to get -4/7.

$\frac{4}{5}-\frac{3}{5}x=\frac{3}{7}x-\frac{4}{7} \\$

Subtract $\frac{3}{7}x\\$ from both sides.

$\frac{4}{5}-\frac{3}{5}x-\frac{3}{7}x=-\frac{4}{7} \\$

Combine $-\frac{3}{5}x\\$ and $-\frac{3}{7}x\\$ to get $-\frac{36}{35}x\\$ .

$\frac{4}{5}-\frac{36}{35}x=-\frac{4}{7} \\$

Subtract 4/5 from both sides.

$-\frac{36}{35}x=-\frac{4}{7}-\frac{4}{5} \\$

The least common multiple of 7 and 5 is 35. Convert -4/7 and 4/5 to fractions with denominator 35.

$-\frac{36}{35}x=-\frac{20}{35}-\frac{28}{35} \\$

Because $-\frac{20}{35} \\$ and $\frac{28}{35}\\$ have the same denominator, subtract them by subtracting their numerators.

$-\frac{36}{35}x=\frac{-20-28}{35} \\$

Subtract 28 from -20 to get -48.

$-\frac{36}{35}x=-\frac{48}{35} \\$

Multiply both sides by $-\frac{35}{36}\\$ , the reciprocal of $-\frac{36}{35}\\$ .

$x=-\frac{48}{35}\left(-\frac{35}{36}\right) \\$

Multiply $-\frac{48}{35}\\$ by $-\frac{35}{36}\\$ by multiplying the numerator by the numerator and the denominator by the denominator.

$x=\frac{-48\left(-35\right)}{35\times 36} \\$

Carry out the multiplications in the fraction $\frac{-48\left(-35\right)}{35\times 36}\\$ .

$x=\frac{1680}{1260} \\$

Reduce the fraction 1680/1260 to its lowest terms by extracting and cancelling out 420.

$\huge \boxed{ \boxed{ \bf \: x=\frac{4}{3} \approx \: 1.33}}$

3 0

3 years ago

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What is the area C in terms of

kifflom [539]

Answer: D

Hope this help

7 0

3 years ago

the daycare recieves a new sandbox. the perimeter is 84 feet and the length is twice as long as the width. what are the dimensti

matrenka [14]

Answer:

Width is 14 ft, length is 28 ft

Step-by-step explanation:

We know that the length is twice as long as the width. This can be represented by L=2W.

The equation to solve this is 84=W+W+L+L. We can replace both the L variables with 2W, since that is what L equals.

84=W+W+2W+2W. We simplifiy to get 84=6W. We divide 84 by 6 and get W=14.

Now that we know the width, finding the length is easier. L=2(14). L=28 ft.

To check our math we can do 28+28+14+14. 56+28=84 ft.

Therefore, the width is 14 ft and the length is 28 ft.

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3 years ago

Would a 40 inch squared picture fill a 5 x 9 picture frame?

statuscvo [17]

Multiple 40*40 to determine the actual square inches. Then multiply 5*9 to determine the square inches of the frame. Compare the two numbers. If 40*40 is bigger than 5*9, then the picture will not fit in the frame. If 40*40 is smaller than 5*9, then the picture will fit in the frame.

40^2= 40 * 40= 160" squared

5*9= 45" squared

A 160" squared picture would be too big for a 45" squared frame.

Hope this helps! :)

3 0

3 years ago

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