3 years ago

CAN YOU PLEASEEE HELP ME IM DESPERATE AND NEED THE ANSWER ASAP

Mathematics

1 answer:

Juliette [100K]3 years ago

6 0

Answer:

6(x-3)(X^2+4)(x+1)=0

real answers:

(x-3)=0

x=3

x+1=0

x=-1

This numbers are not real:

x^2+4=0

x^2=-4

$\sqrt{x}$ = ± $\sqrt{2}$

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