Ask question

Ask question

All categories

3 years ago

10

Suppose you draw a card, put it back in the deck, and draw another one. what is the probability that the first card is a diamond

and the second is a spade?

1 answer:

Bond [772]3 years ago

8 0

9+ 10 = 21
the anser is h

You might be interested in

Can someone help me find x? Ty

Burka [1]

Answer:

x = -2

Step-by-step explanation:

14 - (x + 5) = 3(x + 9) - 10

14 - x - 5 = 3x + 27 - 10

9 - x = 3x + 17

9 = 4x + 17

-8 = 4x

-2 = x

5 0

2 years ago

Math help me please you will be mark as the brainiest I do not have much time left

Black_prince [1.1K]

A little tip: you should put the question in next time :)!

7 0

3 years ago

Based on the Fundamental Theorem of Algebra, how many complex roots does each of the following equations have? Write your answer

mars1129 [50]

Answer:

2, 2, 4, 6, 4

Step-by-step explanation:

Fundamental Theorem of Algebra states that 'An 'n' degree polynomial will have n number of real roots'.

1. The polynomial is given by $x(x^2-4)(x^2+16) = 0$

So, on simplifying we get that, $x(x+2)(x-2)(x^2+16)=0$ .

Since, degree of polynomial is 5, it will have 5 roots.

This gives us that the roots of the equation are x = 0, -2, 2, 4i and -4i

So, the number of complex roots are 2.

2. The polynomial is given by $(x^2+4)(x+5)^2 = 0$

Since, degree of polynomial is 4, it will have 4 roots.

Equating them both by zero, $(x^2+4)= 0$ and $(x+5)^2=0$ gives that the roots of the polynomial are x = 2i, -2i, -5, -5.

So, the number of complex roots are 2.

3. The polynomial is given by $x^6-4x^5-24x^2+10x-3=0$

Since, degree of polynomial is 6, it will have 6 roots.

On simplifying, we get that the real roots of the polynomial are x = -1.75 and x = 4.28.

So, the number of complex roots are 6-2 = 4.

4. The polynomial is given by $x^7+128=0$

Since, degree of polynomial is 7, it will have 7 roots.

On simplifying, we get that the only real root of the polynomial is x = -2.

So, the number of complex roots are 7-1 = 6.

5. The polynomial is given by $(x^3+9)(x^2-4)=0$

Since, degree of polynomial is 5, it will have 5 roots.

Simplifying the equation gives $(x+2)(x-2)(x+\sqrt[3]{9})(x^2-\sqrt[3]{9x}+9^{\frac{2}{3}})=0$

Equating each to 0, we get the real roots of the polynomial is $x=-3^{\frac{2}{3}}$

So, the number of complex roots are 5-1 = 4

6 0

3 years ago

Read 2 more answers

Evaluate x(y-z)2 for =-1,y=5,and z=

Nata [24]

Answer:

The value of $x(y-z)^2$ is -16.

Step-by-step explanation:

We need to evaluate $x(y-z)^2$ for x = -1, y = 5 and let us assume that z = 1

It can be simply done by putting the values of x,y and z in the given expression.

$x(y-z)^2=(-1)(5-1)^2\\\\=-1(4)^2$

We know that the value of 4² = 16

So,

$x(y-z)^2=16\times -1\\\\=-16$

So, the value of $x(y-z)^2$ is -16.

6 0

4 years ago

Which step is included in the graph of the function f(x)=[x-1]? (the brackets are ceiling functions symbols)

KiRa [710]

we are given

f(x)=[x=1]

where bracket means ceiling functions

we know that

Ceiling function returns the least value of the integer that is greater than or equal to the specified number

so, we can check each options

option-A:

$-4\leq x$

At x=-4:

f(x)=[-4-1] =-5

For x<-3:

Let's assume

x=-3.1

f(x)=[-3.1-1] =[-4.1]=-5

so, this interval is TRUE

option-B:

$-2\leq x$

At x=-2:

f(x)=[-2-1] =-3

For x<-1:

Let's assume

x=-1.1

f(x)=[-1.1-1] =[-2.1]=-3

so, this is FALSE

7 0

4 years ago

Read 2 more answers