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arlik [135]
3 years ago
12

Calculate the premiums for the following insurance policies. (Help!!!! Active Quiz)

Mathematics
2 answers:
Sonbull [250]3 years ago
7 0
Automobile insurance: 809.50
comprehensive coverage: 64

Based on the note:
subtract 64: 809.50 - 64 = 745.50
multiply by 150% : 745.50 x 1.5 = 1,118.25
add 64: 1,118.25 + 64 = 1,182.25

The new total is 1,182.25
Blizzard [7]3 years ago
4 0

Answer: Annual premium is $1182.25.

Step-by-step explanation:

Since we have given that

Amount paid for automobile insurance = $809.50

In which Amount for comprehensive coverage includes = $64

So, Amount without comprehensive coverage is given by

\$809.50-\$64\\\\=\$745.50

One year, Marty has two accidents.

so, amount for premium includes 150% of 745.50( Amount without comprehensive coverage) which is given by

\frac{150}{100}\times 745.50\\\\=\$1118.25

Then we include the cost of comprehensive coverage as it is given that it does not change.

1118.25+64\\\\=\$1182.25

Hence, Annual premium is $1182.25.

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the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:

<span>The interquartile range is the difference between the third and the first quartiles.

The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5

The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
6 0
4 years ago
Read 2 more answers
select all equations that have x = 3 as a solution. A. X + 7 = 10 B. 3+ x = 3 C. x • 3 = 1 D. 4 • x = 12 ​
castortr0y [4]

Answer:

A.

Step-by-step explanation:

7+3=10 so it will be A, you're welocme

7 0
3 years ago
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A manager randomly selected 25 large cash transactions at a bank that were made in January. The manager then carefully tracked d
Dmitriy789 [7]

Answer:

0.4629 = 46.29% probability that the manager finds more than two such transactions

Step-by-step explanation:

For each transaction, there are only two possible outcomes. Either there is a procedural error, or there is not. The probability of a procedural error on a transaction is independent of any other transaction. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A manager randomly selected 25 large cash transactions at a bank that were made in January.

This means that n = 25

The chance for a procedural error is 10%

This means that p = 0.1

What is the probability that the manager finds more than two such transactions?

This is:

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{25,0}.(0.1)^{0}.(0.9)^{25} = 0.0718

P(X = 1) = C_{25,1}.(0.1)^{1}.(0.9)^{24} = 0.1994

P(X = 2) = C_{25,2}.(0.1)^{2}.(0.9)^{23} = 0.2659

P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0718 + 0.1994 + 0.2659 = 0.5371

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5371 = 0.4629

0.4629 = 46.29% probability that the manager finds more than two such transactions

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