1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Makovka662 [10]
3 years ago
12

Let C(x)=600+60x be the cost to manufacture x items.Find the average cost per item, to the nearest dollar, to produce 30 items.

Mathematics
1 answer:
QveST [7]3 years ago
6 0

Answer:

Correct answer: B: $80

Step-by-step explanation:

Given the function, C(x) = 600 + 60x, where:

C(x) = represents the total cost to manufacture x items

    x = number of manufactured items

Substitute x = 30 into the given function:

C(30) = 600 + 60(30)

C(30) = 600 + 1800

C(30) = 2400 ← This represents the total cost to produce 30 items.  We need to find out the <u>average cost per item</u>.

Thus, we need to divide $2,400 by 30 to get the average cost of producing each item:

$2,400 / 30 = $80

Therefore, the correct answer is B) $80

Please mark my answers as the Brainliest if you find my explanations helpful :)

You might be interested in
Jason volunteered at the pet shelter twice as many times as keith. Noah volunteered three times more often than jason. Keith vol
Alchen [17]

Answer:

y = 6\cdot z

y - Number of times that Noah volunteered at pet shelter.

z - Number of times that Keith volunteered at pet shelter.

Step-by-step explanation:

After reading the statement of the problem, the following variables are described below:

x - Number of times that Jason volunteered at pet shelter.

y - Number of times that Noah volunteered at pet shelter.

z - Number of times that Keith volunteered at pet shelter.

The following two relations are presented herein:

Noah and Jason

y = 3\cdot x

Jason and Keith

x = 2\cdot z

The relationship between the number of times Noah and Keith volunteered is:

y = 6\cdot z

7 0
3 years ago
Which length is 10 6 times greater than a nanometer?
crimeas [40]
A nanometer (nm) is 10⁻⁹ m.

Therefore
10⁶ x 1 nm = 10⁶(10⁻⁹ m) = 10⁻³ m

By definition,
10⁻³ m = 1 mm (millimeter)

Answer: 1 millimeter
8 0
3 years ago
13 mm<br> 17 mm<br> What would the area of the triangle
Bad White [126]

Answer:

110.5mm

Step-by-step explanation:

Formula : a = hb/2

a = 13(17)/2

221/2 = 110.5

5 0
3 years ago
The Bishop family celebrated a birthday by dining out at a local restaurant. Their bill was $97.45. Mr. Bishop would like to lea
serg [7]
97.45 • 0.18 = 17.54. 97.45 + 17.54 = 114.99. I think this is right.
6 0
3 years ago
Read 2 more answers
Please give an explanation and the answer to this question for 15 points thanks.
Alchen [17]

Answer:

y=29

Step-by-step explanation:

Since the angles are across a vertex from one another, they are congruent and equal. You can also see this by reflecting  or folding it in half through the vertex. They will be the same. This means we can write the following equation and solve using inverse operations:

4y-8=79+y

4y-y-8=79+y-y

3y-8=79

3y-8+8=79+8

3y=87

y=29

4 0
3 years ago
Other questions:
  • An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th
    15·1 answer
  • A 1st degree polynomial function whose graph intercepts the y-axis at 8.
    5·1 answer
  • What is the factored form of 2x^2-7x+6
    8·1 answer
  • Determine the distance between -7 and 7
    12·1 answer
  • What type of rational number is 7 2/0
    5·1 answer
  • 40% of what<br>number is 32?​
    12·2 answers
  • HELP ASAP PLEASE
    11·2 answers
  • Which statements regarding the diagram are correct? Check all that apply. ST ≅ ST by the reflexive property. ∠RWS ≅ ∠UWT because
    14·2 answers
  • If it costs $.25 per square yard to seed an area of grass, how much does it cost to seed in the inside of this track
    9·1 answer
  • What is the area of this figure? <br>​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!