Answer:
We have a + b as;
2 + 3 = 5
Step-by-step explanation:
Here, we want go get the value of a and b
from the second equation, we can get an expression for b
We have this as;
7a - b = 11
Thus,
b = 7a - 11
Now, from here, we can substitute the value of b into the first equation
We have this as;
5a + 4(7a - 11) = 22
5a + 28a -44 = 22
33a = 22 + 44
33a = 66
a = 66/33
a = 2
Recall;
b = 7a - 11
substituting the value of a from above;
b = 7(2) - 11
b = 14 - 11
b = 3
*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*
(21)
Area of a Regular Hexagon:
square units
(22)
Similar to (21)
Area =
square units
(23)
For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:


Hence, area of the hexagon will be:
square units
(24)
Given is the inradius of an equilateral triangle.

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:
Side = 16 units
Area of equilateral triangle =
square units
I believe so. (TRUE). a square has all equal sides so if the figure is just alike, its a reg quad.
1 whole and 1/3 is the answer