Answer:
0.9009
Step-by-step explanation:
Let X be the event that Current will flow
Let Y be the event that the first relay which is 1 is closed
Thus, we can say that every element of Y is in X, but X possesses more elements. Thus, Y ⊂ X.
Thus, we can say that;
P(X ∩ Y) = P(Y)
Thus, given that current flowed, the probability that relay 1 functioned will be expressed as;
P(Y | X) = (P(Y ∩ X))/P(X)
From earlier, we saw that P(X ∩ Y) = P(Y). Thus;
P(Y | X) = P(Y)/P(X)
From the question, P(Y) = 0.9
Since there are 3 relays, then we have;
P(X) = 1 - 0.1³ = 0.999
Thus;
P(Y | X) = 0.9/0.999
P(Y | X) = 0.9009
I’m pretty sure it would be interquartile range, since range is the measure that measures variation within a data set.
P-45>10 add 45 to both sides
p>55
So the caterer had more than 55 pounds originally.
The answer is really 1 5/6 because 5/6 + 2/3=5/6 NOT 7/3 so of course she is wrong
V(-6,3)
subtract 8 from 2, since it is moving to the left but keep the y the same since it is not translated up or down
