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kumpel [21]
2 years ago
8

Find the missing side. Round to the nearest tenth. Х y 390 57 X=[?]

Mathematics
1 answer:
sweet [91]2 years ago
6 0

Answer:It's 46.2

Step-by-step explanation:

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What is the name of the blue ninja turtle (free points i already know) first one gets brainly
Natali5045456 [20]

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It is Leonardo

Step-by-step explanation:

3 0
3 years ago
Can someone please answer these (real answers only)
adell [148]
5. The number of visitors increase in April, spike in August and then decrease in September.

6. December is in winter, therefore many people do not travel during December.

7. There are not a lot of holidays in February and March, so people are either working or going to school instead of visiting.

I hope this helped!
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3 years ago
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HURRY PLEASEEEEEEEEEEE. A coordinate plane. The point (5, 5) is in Quadrant . The point (3, –2) is in Quadrant . The point (–4,
iVinArrow [24]

Answer:

point (5, 5) is in Quadrant: I  (1)

point (3, –2) is in Quadrant: IV   (4)

The point (–4, –4) is in Quadrant: III   (3)

Step-by-step explanation:

3 0
3 years ago
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You are offered two different sales jobs. The first company offers a straight commission of 5% of the sales. The second company
sweet [91]

Answer:$5408

Step-by-step explanation:

The first company offers a straight commission of 5% of the sales. This means the salary or income is 5% of sales made.

The second company offers a salary of $260 per week plus 4% of the sales. This means salary or income

= $260 +4% of 260

= 260 + (4/100)×260

= 260 +(0.04×260)

=260+10.4 = $270.4

Let x = the amount of sales you would have to sell in a week in order for the straight commission offer to be at least as good

5% of x should be greater than or equal to $270.4

0.05x = 270.4

x = 270.4/0.05 =$5408

The sales should be greater than or equal to $5408

3 0
3 years ago
☆pls help no one has helped me and I'm so confused! ​
motikmotik

Answer:

Step-by-step explanation:

a). \frac{5\pm\sqrt{-4}}{3} = \frac{5}{3}\pm \frac{\sqrt{-4}}{3}

               = \frac{5}{3}\pm\frac{2\sqrt{(-1)} }{3}

               = \frac{5}{3}\pm\frac{2i}{3} [Since, i = \sqrt{(-1)}]

b). \frac{10\pm\sqrt{-16}}{2} = \frac{10}{2}\pm \frac{\sqrt{-16}}{2}

                  = 5\pm \frac{4\sqrt{-1}}{2}

                  = 5 ± 2i [Since, i = \sqrt{(-1)}]

c). \frac{-3\pm \sqrt{-144}}{6} = -\frac{3}{6}\pm \frac{\sqrt{-144}}{6}

                    = -\frac{3}{6}\pm \frac{12\sqrt{-1}}{6}

                    = -\frac{1}{2}\pm 2\sqrt{-1}

                    = -\frac{1}{2}\pm 2i [Since, i = \sqrt{(-1)}]

4 0
2 years ago
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