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kumpel [21]
2 years ago
8

Find the missing side. Round to the nearest tenth. Х y 390 57 X=[?]

Mathematics
1 answer:
sweet [91]2 years ago
6 0

Answer:It's 46.2

Step-by-step explanation:

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lakkis [162]

Answer:

I think y−4=3(x−1)

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Question 4 Given: f(x) = -3x – 3 and g(x) = x2 + 5 Find (f - g) ().​
Aleonysh [2.5K]

Answer:

We get \mathbf{(f-g)(x)= -x^2-3x-8}

Step-by-step explanation:

We are given:

f(x) = -3x - 3\\ g(x) = x^2 + 5

We need to find (f-g)(x) (assuming there is x in the bracket, i.e. (f - g) () should be (f-g)(x))

We would simply subtract f(x) and g(x)

(f-g)(x)\\= -3x-3-(x^2+5)\\Multiply\:minus\:sign\:with\:terms\:inside\:the\:bracket\\=-3x-3-x^2-5\\Combining\:like\:terms:\\=-x^2-3x-3-5\\=-x^2-3x-8

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5 0
2 years ago
Water weighs about 8.34 pounds per gallon
Svetach [21]
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3 years ago
A rectangular swimming pool is twice as long as it is wide. A small concrete sidewalk surrounds the pool and is a constant 2 fee
Naddika [18.5K]

Answer:

The dimensions of the pool are:

Width: 8.944 feet

Length: 17.888 feet

Step-by-step explanation:

From Geometry, the area of a rectangle (A), measured in square feet, is determined by the following equations:

A = w\cdot l (1)

Where:

w - Width, measured in feet.

l - Length, measured in feet.

If we know that w = x, l = 2\cdot x and A = 160\,ft^{2}, then we get the following second order polynomial:

2\cdot x^{2}-160 = 0 (1)

And we solve the expression for x:

2\cdot x^{2} = 160

x^{2} = 80

x = \sqrt{80}\,ft

x \approx 8.944\,ft

Then, the dimensions of the pool are, respectively:

w \approx 8.944\,ft and l \approx 17.888\,ft

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3 years ago
Classify the absolute value statements based on their values. |3| |-3| |-4| |4| |-5| |5|
Fittoniya [83]
The answers would be 3, 3, 4, 4, 5, 5. those are the answers. I don't know if that is what you wanted me to answer or not.
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