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Nadusha1986 [10]
3 years ago
5

Can someone please help me, thanks!

Mathematics
1 answer:
igomit [66]3 years ago
7 0

I think you should give more points for the problems so that you can get more of a chance to get your problems solved.

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El prestigioso hotel Los Cisnes, cobra la recepción a las delegaciones extranjeras de acuerdo con la siguiente política: Las del
dem82 [27]

Answer:

"x" cantidad de personas, que será igual a

f(x) = $10x   Si   x < 30

f(x) = $9.5x si x ≥ 30

Si tenemos que son 29 personas entonces el costo es de:

f(x) = $10*29 = $290

Si incluye un miembro adicional

f(x) = $9.5*30 = $285

Ahorra un total de: $290 - $285 = $5

8 0
3 years ago
Paul traded 13 baseball card to Dan for 4 new packs of 6 cards each. Paul lost 3 cards. He now has 75 cards. How many cards did
melomori [17]

Answer:

The number of cards Paul had at the beginning was 64 cards

Step-by-step explanation:

Here we have a word problem as follows

Paul traded 13 baseball card to Dan for 4 new packs of 6 card each

Number of cards received from Dan = 6 × 4 = 24

Number of cards traded to Dan = 13

Net number of cards traded = 24 - 13 = 11

Total number of cards Paul now has = 75 cards

Therefore since Paul gained 11 cards to make his total number of cards = 75, then;

The initial amount of cards Paul had = 75 - 11 = 64 cards.

3 0
3 years ago
Find the value of y if 2y +4=8​
Airida [17]

Answer:

\huge\colorbox{violet}{✏﹏ \: ᴀɴsᴡᴇʀ \: }

2y + 4 = 8 \\ 2y = 8 - 4 \\ 2y = 4 \\ y =  \frac{4}{2}  \\ y = 2

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

\huge\red{ \mid{ \underline{ \overline{ \tt ꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐ }} \mid}}

5 0
3 years ago
Read 2 more answers
A pair of inline skates, regularly priced at $180, is now on sale at a 30% discount. What is the sale price of the skates?
Alex_Xolod [135]
180 x (1-30%)
=180 x 0.7
=$126
7 0
3 years ago
Read 2 more answers
In a data distribution, the first quartile, the median and the means are 30.8, 48.5 and 42.0 respectively. If the coefficient sk
RUDIKE [14]

Answer:

a) The third quartile Q₃ = 56.45

b) Variance \mathbf{ \sigma^2 =2633.31}

Step-by-step explanation:

Given that :

Q_1  =  30.8

Median Q_2 =  48.5

Mean  = 42

a) The mean is less than median; thus the expression showing the coefficient of skewness is given by the formula :

SK = \dfrac{Q_3+Q_1-2Q_2}{Q_3-Q_1}

-0.38 = \dfrac{Q_3+30.8-2(48.5)}{Q_3-30.8}

-0.38Q_3  + 11.704  =  Q_3  +30.8  - 97

1.38Q_3  =  77.904

Divide both sides by 1.38

Q_3 = 56.45

b) The objective here is to determine the approximate value of the variance;

Using the relation

SK_p = \dfrac{Mean- (3*Median-2 *Mean) }{\sigma}

-0.38= \dfrac{42- (3 *48.5-2*42) }{\sigma}

-0.38= \dfrac{(-19.5) }{\sigma}

-0.38* \sigma = {(-19.5) }{}

\sigma =\dfrac {(-19.5) }{-0.38 }

\sigma =51.32

Variance =  \sigma^2 =51.32^2

\mathbf{ \sigma^2 =2633.31}

7 0
3 years ago
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