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BlackZzzverrR [31]
3 years ago
14

Can you please help with this

Mathematics
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer:

Exercise 1 : a. 4 ; b. -4

Exercise 2 : a. +7 positive/right ; b. -7 ; c. -7 negative/left

Step-by-step explanation:

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Hello,

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\boxed{x^2=-8y}

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(a,b)\ is \ the\ focus\\y=k\ is \ the\ directrice\\\\Formula\ to\ use:\ y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\Here: \ a=0,\ b=-2, \ k=2\\\\y=\dfrac{(x-0)^2}{2(-2-2)} +\dfrac{-2+2}{2} \\\\so\ y=-\dfrac{x^2}{8} \\\\or\ x^2=-8y

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