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Novay_Z [31]
3 years ago
12

What is the range of the function represented by these ordered pairs?

Mathematics
1 answer:
Finger [1]3 years ago
6 0

Answer:

Choice 2

Step-by-step explanation:

Range is talking about the y value of the coordinates. Choice 2 has all the y value in the function

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8. Write the composition of translations T(7,8) •T(-3,-4)<br> as one translation.
11111nata11111 [884]

Answer:

T (4, 8)

Step-by-step explanation:

T(7,8) •T(-3,-4) = T ( -3+7, -4+8) = T( 4, 4 )

Instead of moving

(3 units to the left, and 4 units down) then ( 7units to the right and 8 units up) we could get to the same place by moving

( 4 units to the right and 4 units up)

8 0
3 years ago
What is the equation of the line that passes through the point (-3,1) and has a slope of​ 4/3?
kkurt [141]

Answer:

3y-4x=9

Step-by-step explanation:

using y-y1/ x- x1=m

y-1/x--3=4/3

y-1/x+3= 4/3

3(y+1)=4(x+3)

3y+3= 4x+12

3y-4x=12-3

3y-4x=9

8 0
3 years ago
The function of f(x)=8√x gives the speed in feet per second (ft/s) of a free falling object after it has fallen x feet (ignoring
Juliette [100K]

Answer:

c. 55.4 ft/s

Step-by-step explanation:

Speed of the object is represented by the function:

f(x)=8\sqrt{x}

where x represents the number of feet the object has fallen. We have to find the speed of the object after it has fallen 48 feet. This means we have to find f(x) for x = 48. Substituting x = 48 in above equation we get:

f(48)=8\sqrt{48}\\\\ =8\sqrt{16 \times 3}\\\\ =8\sqrt{4^{2} \times 3}\\\\ = 8 \times 4 \sqrt{3}\\\\ =32\sqrt{3}\\\\ = 32 \times 1.732\\\\ = 55.4

Thus, rounded to nearest tenth, the speed of the object after it has fallen 48 feet would be 55.4 ft/s

7 0
3 years ago
Find the value of x and the measure of the angle labeled 2x°
zimovet [89]

Answer:

112=64+2x

112-64=2x

48=2x

x=48/2

x=24

so,2x=2×24=48

C

8 0
3 years ago
The lowest temperature on record in the United States was -80 Degrees at prospect creek camp Alaska. The highest recorded temper
Aleksandr [31]
Answer: (D) and (A)
3 0
3 years ago
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