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3 years ago

HELP PLEASE WILL MARK BRAINLIEST!!

Mathematics

1 answer:

kakasveta [241]3 years ago

8 0

7Cos33. use Soh Cah Toa to remember Sine Cosine and Tangent. SINE opposite hypotnuse,, COSINE, Adjacent Hypotnuse,, TANGENT Opposite adjacent. so the problem starts as Cos33°= Adjacent/7 . but to type it in the calculator, it becomes 7Cos33° . (think of adjacent as “X” and that you need to get X alone,, so you multiply 7 on both sides to get X alone. We multiply bc multiplication undos division)

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Answer:

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Step-by-step explanation:

Given

$g(x) = \frac{1}{6}(8)^{x-5}$

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Required

Solve

Substitute 9 for x in $g(x) = \frac{1}{6}(8)^{x-5}$

$g(9) = \frac{1}{6}(8)^{9-5}$

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Remove bracket

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$g(9) = \frac{1* 4096}{6}$

$g(9) = \frac{4096}{6}$

Simplify fraction

$g(9) = \frac{2048}{3}$

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