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ladessa [460]
4 years ago
8

Which theorem or postulate justifies that HEF ~ HGE?

Mathematics
2 answers:
ruslelena [56]4 years ago
8 0
<span>AA similarity postulate</span>
d1i1m1o1n [39]4 years ago
3 0
<span>A. AA similarity postulate
since angle HGE=angle HEF and angle EHG=angle FHE</span>
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Complete the function table and write the function rule.
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Y = x but what is pi

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A graphical depiction of a frequency distribution for numerical data in the form of a column chart is called a
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A histogram

Step-by-step explanation:

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Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
3 years ago
Solve each inequality of -4x -2&lt;8
FromTheMoon [43]
<span>-4x -2<8
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-4x<10
Divide -4 on both sides
Final Answer: x > -10/4 or -2 1/2 *Both answers are equivalent to each other.
</span>
6 0
3 years ago
Alaina has $28 in her account. She wants to purchase a pair of shoes that costs $45. If Alaina makes the purchase, which integer
k0ka [10]
Alaina has $28 in her account and wants to buy shoes worth $45

So $28-$45=$-17

Her account status will be $ - 17

Hope this helps
3 0
4 years ago
Read 2 more answers
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