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kirill115 [55]
3 years ago
9

Find the product:−5/3(−2/3)(−18)A) −20 B) −35/3C) 35/3D) 20

Mathematics
2 answers:
Kobotan [32]3 years ago
7 0

Answer:

I got D. 20

Step-by-step explanation:

-5/3 times -2/3 equals 10/9

10/9 times -18 equals -20

Hope this helps dude ^-^

dolphi86 [110]3 years ago
6 0
The answer is A because when you multiply them all together you get -180/9 and simply to get -20
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600g - 210d + -0.032= 15yr or c
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7(x + 2)  + 12x(x + 2)

(2x - 4)(7 + 12x)

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(2x + 81)( - 7x)

5 0
4 years ago
What kind of force can an. Elastic material exert
marusya05 [52]

Answer:

i hope this helps "Elasticity is the ability of a material to return to its original shape after being stretched or compressed. When an elastic material is stretched or compressed, it exerts elastic force. This force increases the more the material is stretched or compressed."

Step-by-step explanation:

7 0
3 years ago
Which inequality correctly compares 1/3, 5/6, and 3/5?
Ilya [14]

For this case we have the following fractions:

\frac {1} {3} = 0.3333\\\frac {5} {6} = 0.8333\\\frac {3} {5} = 0.6

So we have to:

0.3333

This is equivalent to:

\frac {1} {3}

Answer:

\frac {1} {3}

The answer is Option A

6 0
4 years ago
In an isosceles trapezoid the length of a diagonal is 25 cm and the length of an altitude is 15 cm. Find the area of the trapezo
andreev551 [17]

Answer:

The area of the trapezoid is 525\ cm^{2}

Step-by-step explanation:

we know that

The area of a isosceles trapezoid is equal to the area of two isosceles right triangles plus the area of a rectangle

step 1

<em>Find the area of the  isosceles right triangle</em>

Remember that

In a isosceles right triangle the height is equal to the base of the triangle

we have

h=15\ cm

so

b=15\ cm

The area is equal to

A=\frac{1}{2}(b)(h)

substitute the values

A=\frac{1}{2}(15)(15)=112.5\ cm^{2}

step 2

Find the area of the rectangle

The area of the rectangle is equal to

A=LW

we have

W=15\ cm -----> is the height of the trapezoid

d=25\ cm  -----> the diagonal of the rectangle

Applying the Pythagoras Theorem

25^{2}=L^{2}+15^{2}\\L^{2}=25^{2}-15^{2} \\ L^{2} =400\\L=20\ cm

The area of the rectangle is

A=(20)(15)=300\ cm^{2}

step 3

Find the area of the trapezoid

A=2(112.5\ cm^{2})+300\ cm^{2}=525\ cm^{2}

6 0
4 years ago
Read 2 more answers
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