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zalisa [80]
3 years ago
9

The lengths of two sides of a triangle are 14 inches and 4 inches which of following is the dimensions is the third side of the

triangle?
10 in
11 in
8 in
9 in

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
5 0

The sum of any 2 sides of a triangle must be bigger than the length of the third side.

Given 2 sides we can make 3 inequality's to solve:

Let X = the length of the third side.

#1) 14 + 4 > x

18 > x

#2) 14 + X > 4

x > 4-14 = -10 ( This doesn't work because we can't have a side length that is a negative number)

#3) 4 + X > 14

x >14-4 = 10

So using #1 and #3 X has to be greater than 10 and less than 18

The length of the third side is 11.

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GarryVolchara [31]

Answer:

P(Ice Cream|Frogtown) = 67.4\%

Step-by-step explanation:

Given

The attached plot

Required

P(Ice Cream|Frogtown)

This is calculated as:

P(Ice Cream|Frogtown) = \frac{P(Ice\ Cream\ n\ Frogtown)}{P(Frogtown)}

From the attachment;

P(Ice\ Cream\ n\ Frogtown) = 0.31

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P(Ice Cream|Frogtown) = \frac{P(Ice\ Cream\ n\ Frogtown)}{P(Frogtown)}

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P(Ice Cream|Frogtown) = 0.6739

Express as percentage

P(Ice Cream|Frogtown) = 0.6739 * 100\%

P(Ice Cream|Frogtown) = 67.39\%

P(Ice Cream|Frogtown) = 67.4\% -- approximated

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Ben jogged 4 and 1/2 miles in 1 and 1/4 hours at a constant rate. How far did Ben jog in one hour? *
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let's firstly convert the mixed fractions to improper fractions and then proceed.

\stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}}~\hfill \stackrel{mixed}{1\frac{1}{4}}\implies \cfrac{1\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{5}{4}} \\\\[-0.35em] ~\dotfill

\begin{array}{ccll} miles&hours\\ \cline{1-2} \frac{9}{2}&\frac{5}{4}\\[1em] x&1 \end{array}\implies \cfrac{~~ \frac{9}{2}~~}{x}=\cfrac{~~ \frac{5}{4}~~}{1}\implies \cfrac{~~ \frac{9}{2}~~}{\frac{x}{1}}=\cfrac{5}{4}\implies \cfrac{9}{2}\cdot \cfrac{1}{x}=\cfrac{5}{4} \\\\\\ \cfrac{9}{2x}=\cfrac{5}{4}\implies 36=10x\implies \cfrac{36}{10}=x\implies \cfrac{18}{5}=x\implies 3\frac{3}{5}=x

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