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deff fn [24]
3 years ago
6

Helpppppppppppppppppppppppppppppp

Mathematics
2 answers:
artcher [175]3 years ago
8 0

your answer to 55*30 would be 1650


Dmitry [639]3 years ago
6 0

Answer:

It would be 2035

Step-by-step explanation: 55*30=1650 then 1650+385=2035


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Find the midpoint between the points (7, -2) and (-4, 2). Write your answer in the proper form using parentheses
Elan Coil [88]

Answer:

( 1.5, 0)

Step-by-step explanation:

1. Find the coordinates ; in this case (7,-2) and (-4, 2)

2. Plug it into the formula (x1 + x2 ÷ 2 ) , (y1 + y2 ÷ 2)

3. ( 7 +  -4 ÷2) = 1.5    And    ( -2 + 2 ÷ 2) = 0

4. Therefore, the midpoint is ( 1.5, 0 )

                                         

3 0
3 years ago
A model rocket is 3 inches long. the real rocket is 120 ft long. what is the unit rate that describes the relationship of the re
lora16 [44]

Answer:

40 ft/in

Step-by-step explanation:

There is 40 feet for every inch of the model

4 0
3 years ago
Read 2 more answers
Explain why there must be at least two lines on any given plane
Lesechka [4]
BECAUSE THERE IS A Y AXIS AND AN X AXIS THOSE R THE 2 GIVIN LINES
6 0
3 years ago
the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years​
Yuliya22 [10]

Answer:  125 g

<u>Step-by-step explanation:</u>

A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k

\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125

8 0
3 years ago
Costs for standard veterinary services at a local animal hospital follow a Normal distribution with a mean of $72 and a standard
Romashka [77]

Answer:

P(32

And we can find this probability with this difference:

P(-1.905

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-1.905

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the costs of services of a population, and for this case we know the distribution for X is given by:

X \sim N(72,21)  

Where \mu=72 and \sigma=21

We are interested on this probability

P(32

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(32

And we can find this probability with this difference:

P(-1.905

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-1.905

8 0
3 years ago
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