Answer:
True except when its 0 or 1 squared in which case would be false
Step-by-step explanation:
0^2=0
1^2=1
$3
Hope this helps.
Each Piece costs .07 cents. Found this out by dividing 2.10 by 3. Then add .07 to 2.10 :)
To solve this problem, what we have to do is to calculate
for the z scores of each condition then find the probability using the standard
normal probability tables for z.
The formula for z score is:
z = (x – u) / s
where,
x = sample value
u = sample mean = 23 days
s = standard deviation = 1 day
A. P when x < 21 days
z = (21 – 23) / 1
z = -2
Using the table,
P = 0.0228
Therefore there is a 2.28% probability that the hatching
period is less than 21 days.
B. P when 23 ≥ x ≥ 22
<span>z (x=22) = (22 – 23) / 1 = -1</span>
P (z=-1) = 0.1587
z (x=23) = (23 – 23) / 1 = 0
P (z=0) = 0.5
P = 0.5 - 0.1587 = 0.3413
Therefore there is a 34.13% probability that the hatching
period is between 22 and 23 days.
C. P when x > 25
z = (25 – 23) / 1
z = 2
P = 0.9772
This is not yet the answer since this probability refers
to the left of z. Therefore the correct probability is:
P true = 1 – 0.9772
P true = 0.0228
<span>Therefore there is a 2.28% probability that the hatching
period is more than 25 days.</span>
Answer:
x=3
Step-by-step explanation: too much math to put here
Answer:
$20,520 at the end of the year
Step-by-step explanation:
A = P(1 + rt)
A = Total Accrued Amount (principal + interest)
P = Principal Amount
I = Interest Amount
r = Rate of Interest per year in decimal; r = R/100
R = Rate of Interest per year as a percent; R = r * 100
t = Time Period involved in months or years
P = $18,000
r = .14
t = 1
A = 18,000 (1+ ( .14 * 1 ) )
A = 18,000 (1 +.14)
A = 18,000 (1.14)
A = 20,520
$20,520 at the end of the year
