NEED HELP ASAP!!!!!!!

Sandy drives in town at a rate of 25 miles per hour. It takes her 15 minutes to drive to the store. How far is it to the store?

Phantasy [73]

Answer: 6.25 miles

Step-by-step explanation:

Convert the 15 minutes to 1/4 hr or .25

now multiply 25*.25=6.25 miles

6 0

3 years ago

The following data show the scores of some students in a competition:

Dima020 [189]

The box plot that represents the data is a box plot titled "Scores of Participants" and labeled "Score" uses a number line from 10 to 35 with primary markings and labels at 10, 15, 20, 25, 30, and 35. The box extends from 13 to 27 on the number line. A line in the box is at 24. The whiskers end at 11 and 31.(second option)

<h3>Which box plot represents the data?</h3>

A box plot is used to study the distribution and level of a set of scores. The whiskers represent the minimum and maximum values.

On the box, the first line to the left represents the lower (first) quartile. The next line on the box represents the median. The third line on the box represents the upper (third) quartile. 75% of the scores represents the upper quartile.

The data arranged in ascending order : 11, 13, 23, 24, 24, 27, 31

Median = 24

First quartile = 1/4 x (7 + 1) = 2nd term =13

Third quartile = 3/4 x (7 + 1) = 6th term = 27

To learn more about box plots, please check: brainly.com/question/27215146

#SPJ1

6 0

1 year ago

Worth 75 points!! Need help with calculus

Keith_Richards [23]

The correct answer is:

2u-v=7(5i-3j)

Therefore, 5, and 3 go inside the box.

4 0

2 years ago

An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s

UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= $\frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }$

a) 95% CI

(X[bar]_1 - X[bar]_2) ± $t_{n_1 + n_2 - 2}$ * $Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }$

Sa²= $\frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}$ = $\frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}$ = 0.5

Sa= 0.707ç

$t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306$

(4.7-6.9) ± 2.306* $(0.707\sqrt{\frac{1}{5}+\frac{1}{5} })$

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0

3 years ago

I need help with this practice problem solving This is trigonometry from my ACT prep guide

Novay_Z [31]

Take into account, that in general, a cosine function of amplitude A, period T and vertical translation b, can be written as follow:

$f(x)=A\cos (\frac{2\pi}{T}x)+b$

In the given case, you have:

A = 4

T = 3π/4

b = -3

By replacing you obtain:

$\begin{gathered} f(x)=4\cos (\frac{2\pi}{\frac{3\pi}{4}}x)-3 \\ f(x)=4\cos (\frac{8}{3}x)-3 \end{gathered}$

Hence, the answer is:

f(x) = 4cos(8/3 x) - 3

6 0

6 months ago