Answer:
The price for each pound of tuna is not always the same.
Step-by-step explanation:
What we do is divide the price by the amount of tuna to find the price for each amount of tuna
For the 1st one, we have $8 for 2 tuna so we do 8/2
8/2 = 4
For the 2nd we have $16 for 4 so we do 16/4
16/4 = 4
For the 3rd, we have $27 for 9 so we do 27/9
27/9 = 3
f(x)= -2x-3
Step-by-step explanation:
Step 1:
Let the sequence given here is -5, -7, -9, -11, -13 ......
Here the first term (a₁) of sequence is -5
And the common difference between the numbers in the sequence is
d= (-7-(-5)) = -7+5 = -2
Let the number of terms be x
Step 2;
To find the sequence function basic arithmetic sequence formula is
aₙ = a₁ + d( x-1)
Applying the values we get
f(X) = -5 + ((-2)(X-1))
on simplification
f(X) = -5 + (-2X+2)
f(X)= -5+2-2X
f(X)= -3-2X
Answer:
Point E on the number line represents the approximate volume of a cylinder with a radius of 4 units and height of 4 units.
Step-by-step explanation:
It is given that the radius of the cylinder is 4 units and the height of the cylinder is 4 units.
The volume of the cylinder is

Where, r is radius and h is height of the cylinder.
Substitute r=4, h=4, π=3.14 in the above formula.


The volume of the cylinder is 200.96. Therefore, point E on the number line represents the approximate volume of a cylinder with a radius of 4 units and height of 4 units.
Answer:
A
Step-by-step explanation:
Sine we can figure out side XY by using Pythagorean Theorem (A^2+B^2=C^2) and find that XY= 5, We can use Soh Cah Toa (The ways I remember to use value charts) and we know that Cosine uses Adjacent over Hypotenuse in which therefore the answer would be 5/13
Answer:
(a) 0.40
(b) 0.049
(c) 
(d) Explained below
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:

The standard deviation of this sampling distribution of sample proportion is:

Given:
n = 100
p = 0.40
As <em>n</em> = 100 > 30 the Central limit theorem is applicable.
(a)
Compute the expected value of
as follows:

The expected value of
is 0.40.
(b)
Compute the standard error of
as follows:

The standard error of
is 0.049.
(c)
The sampling distribution of
is:

(d)
The sampling distribution of p show that as the sample size is increasing the distribution is approximated by the normal distribution.