Answer:
Solution given:
now
f(x)+g(x)=....(1)
now
factoring x²+6x-40
we get
x²+10x-4x-40
x(x+10)-4(x+10)
(x+10)(x-4)
now substituting in equation 1 ,we get
f(x)+g(x)=
taking l.c.m
=
=now
opening bracket
=
So
answer is :
B.
The area of a rectangle is length x width. We can find the 3 areas of the rectangles with this formula:
20 x 5 = 100
100 yd²
15 x (20-14) = 90
90 yd²
14 x 10 = 140
140 yd²
The area of a trapezoid is 1/2(b1+b2)h
In this problem:
b1=25-15-5
b1=5
b2=10
h=20-14
h=6
We can then plug this into the formula:
A = 1/2(5+10)(6)
A = 1/2(15)(6)
A = 45 yd²
We can then get the area of the whole polygon by adding up the areas of the three rectangles and trapezoid:
A = 100+90+140 + 45
A = 375 yd²
Answer:
So first, let's substiute the variables into numbers based on your problem. We get -(-1)-(5)^2+3(-1)(5). If we solve that expression, we will get -39. So, your answer is -39. Hope this helps and good luck
Step-by-step explanation:
Looks like you did most of it.
The next step would be setting them equal to 105, like the problem suggests.
Then we can plug back in to find the numbers.
The three numbers are .
Hope this helps.
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