Answer:
The probability is 0.3576
Step-by-step explanation:
The probability for the ball to fall into the green ball in one roll is 2/1919+2 = 2/40 = 1/20. The probability for the ball to roll into other color is, therefore, 19/20.
For 25 rolls, the probability for the ball to never fall into the green color is obteined by powering 19/20 25 times, hence it is 19/20^25 = 0.2773
To obtain the probability of the ball to fall once into the green color, we need to multiply 1/20 by 19/20 powered 24 times, and then multiply by 25 (this corresponds on the total possible positions for the green roll). The result is 1/20* (19/20)^24 *25 = 0.3649
The exercise is asking us the probability for the ball to fall into the green color at least twice. We can calculate it by substracting from 1 the probability of the complementary event: the event in which the ball falls only once or 0 times. That probability is obtained from summing the disjoint events: the probability for the ball falling once and the probability of the ball never falling. We alredy computed those probabilities.
As a result. The probability that the ball falls into the green slot at least twice is 1- 0.2773-0.3629 = 0.3576
Hello!
To be perpendicular to x = 4, the line must be y = something. This eliminates answer choices #2 and #4. Also, to pass through the point (.5, 7), the line must be y = 7.
So answer choice #3.
Hope this helps!! Let me know if you have ANY questions.
<h3>
Answer: 0.34</h3>
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Explanation:
A = 0.61 is given to us
Pumpkin B travels 0.28 of a mile further than A does, so,
B = A+0.28 = 0.61+0.28 = 0.89
Pumpkin B travels 0.89 of a mile.
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Pumpkin C travels 0.06 of a mile more than B does, which means,
C = B + 0.06
C = 0.89 + 0.06
C = 0.95
Pumpkin C travels 0.95 of a mile.
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The last thing to do is to subtract the values of C and A
C - A = 0.95 - 0.61 = 0.34
Pumpkin C travels 0.34 of a mile further compared to pumpkin A.
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Side note: if you want to convert from miles to feet, then multiply by 5280.
For instance, 0.61 miles = 0.61*5280 = 3,220.8 feet.
First one is 1 x 10^6
second is 2 x 10^8
third one is 157 times
The zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2
<h3>How to determine the zeros of the function?</h3>
The function is given as:
f(x) = x^3 + 3x^2 + 2x
Factor out x in the above function
f(x) = x(x^2 + 3x + 2)
Set the function to 0
x(x^2 + 3x + 2) = 0
Factorize the expression in the bracket
x(x + 1)(x + 2) = 0
Split the expression
x = 0, x + 1 = 0 and x + 2 = 0
Solve for x
x = 0, x = -1 and x = -2
Hence, the zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2
Read more about zeros of function at
brainly.com/question/20896994
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